Java中List的排序

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這裡是一個類中類去實現條件優先排序的問題

package com.sun;import java.util.ArrayList;import java.util.Arrays;import java.util.Collections;import java.util.Comparator;import java.util.List;public class Demo {public Demo() {// TODO Auto-generated constructor stub}/** * @param args */public static void main(String[] args) {// TODO Auto-generated method stubint a= 0;Dob db  = new Dob();Dob db1  = new Dob();Dob db2  = new Dob();db.setName("sun");db.setAge(20);db.setSex(3);db1.setName("zhi");db1.setAge(22);db1.setSex(1);db2.setName("yan");db2.setAge(21);db2.setSex(2);List<Dob> as = new ArrayList<Dob>();System.out.println("as="+as.size());as.add(db);as.add(db1);as.add(db2); Collections.sort(as, new Comparator<Dob>() {//比較。如果年齡不同先比較年齡 ，相同就比較性別            public int compare(Dob arg0, Dob arg1) {            int flg = arg0.getAge().compareTo(arg1.getAge());            if(flg==0){             return arg0.getSex().compareTo(arg1.getSex());            }else{             return arg0.getAge().compareTo(arg1.getAge());            }                           }        });for (Dob p : as) {            System.out.println(p.getName());            System.out.println(p.getAge());        }System.out.println("as="+as.size());}}class Dob {public String  name;public Integer age;public Integer sex;public String getName() {return name;}public void setName(String name) {this.name = name;}public Integer getAge() {return age;}public void setAge(Integer age) {this.age = age;}public Integer getSex() {return sex;}public void setSex(Integer sex) {this.sex = sex;}}

　　

Java中List的排序