PHP計算兩個GPS點之間的距離

下面是PHP計算兩個GPS點距離的函數：

PHP計算兩個GPS點之間的距離
Mysql計算兩GPS座標的距離
javascript計算兩個GPS點之間的距離

#lon為經度，lat為緯度，一定不要弄錯了哦 function <span>distance</span>($lon1, $lat1, $lon2, $lat2){ return (2*ATAN2(SQRT(SIN(($lat1-$lat2)*PI()/180/2) *SIN(($lat1-$lat2)*PI()/180/2)+ COS($lat2*PI()/180)*COS($lat1*PI()/180) *SIN(($lon1-$lon2)*PI()/180/2) *SIN(($lon1-$lon2)*PI()/180/2)), SQRT(1-SIN(($lat1-$lat2)*PI()/180/2) *SIN(($lat1-$lat2)*PI()/180/2) +COS($lat2*PI()/180)*COS($lat1*PI()/180) *SIN(($lon1-$lon2)*PI()/180/2) *SIN(($lon1-$lon2)*PI()/180/2))))*6378140; }

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#lon為經度，lat為緯度，一定不要弄錯了哦 functiondistance($lon1,$lat1,$lon2,$lat2){ return(2*ATAN2(SQRT(SIN(($lat1-$lat2)*PI()/180/2) *SIN(($lat1-$lat2)*PI()/180/2)+ COS($lat2*PI()/180)*COS($lat1*PI()/180) *SIN(($lon1-$lon2)*PI()/180/2) *SIN(($lon1-$lon2)*PI()/180/2)), SQRT(1-SIN(($lat1-$lat2)*PI()/180/2) *SIN(($lat1-$lat2)*PI()/180/2) +COS($lat2*PI()/180)*COS($lat1*PI()/180) *SIN(($lon1-$lon2)*PI()/180/2) *SIN(($lon1-$lon2)*PI()/180/2))))*6378140; }

調用方法：

echo distance(39.91917,116.3896,39.91726,116.3940);

1	echodistance(39.91917,116.3896,39.91726,116.3940);

以上就介紹了PHP計算兩個GPS點之間的距離，包括了方面的內容，希望對PHP教程有興趣的朋友有所協助。

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