PHP計算兩個經緯度之間的距離

來源:互聯網
上載者:User
  1. function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) {
  2. $theta = $longitude1 - $longitude2;
  3. $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta)));
  4. $miles = acos($miles);
  5. $miles = rad2deg($miles);
  6. $miles = $miles * 60 * 1.1515;
  7. $feet = $miles * 5280;
  8. $yards = $feet / 3;
  9. $kilometers = $miles * 1.609344;
  10. $meters = $kilometers * 1000;
  11. return compact('miles','feet','yards','kilometers','meters');
  12. }
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用法:
  1. $point1 = array('lat' => 40.770623, 'long' => -73.964367);
  2. $point2 = array('lat' => 40.758224, 'long' => -73.917404);
  3. $distance = getDistanceBetweenPointsNew($point1['lat'], $point1['long'], $point2['lat'], $point2['long']);
  4. foreach ($distance as $unit => $value) {
  5. echo $unit.': '.number_format($value,4).'
    ';
  6. }
  7. ?>
複製代碼
PHP
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