PHP調用mysql函數報錯

PHP調用mysql函數出錯


Book-O-Rama Search Result

Book-O-Rama Search Results

$searchtype = $_POST['searchtype'];
$searchterm = trim($_POST['searchterm']);
if (!$searchtype || !$searchterm)
{
echo 'You have not entered search details. Please go back and try again.';
exit;
}

if (!get_magic_quotes_gpc())
{
$searchtype = addslashes($searchtype);
$searchterm = addslashes($searchterm);
}

$db = new mysqli('localhost', 'bookorama', 'bookorama123', 'books');
if (mysqli_connect_error())
{
echo 'Error: Could not connect to database. Please try again later.';
exit;
}

$db->select_db("books");

//$query = "select * from books where ".$searchtype." like '%".$searchterm."%'";
$query = "select * from books where ". $searchtype."="."'$searchterm'" ;
//$query = "select * from books";
echo "$query\n";

$result = $db->query($query);
$num_results = $result->num_rows;
echo "

Number of books found: ".$num_results."

";

for ($i = 0; $i < $num_results; $i++)
{
/* 此段被注釋的代碼運行出錯，錯誤在於$result->fetch_assoc();
$result->fetch_assoc();
echo "

".($i+1).". Title: ";
echo htmlspecialchars(stripslashes($row['title']));

echo "
Author: ";
echo stripslashes($row['author']);

echo "
ISBN: ";
echo stripslashes($row['isbn']);

echo "
Price: ";
echo stripslashes($row['price']);

echo "

";
*/

//下面的代碼運行OK
$row = $result->fetch_row();

echo "

".($i+1).". Title: ";
echo htmlspecialchars(stripslashes($row[2]));

echo "
Author: ";
echo stripslashes($row[1]);

echo "
ISBN: ";
echo stripslashes($row[0]);

echo "
Price: ";
echo stripslashes($row[3]);

echo "

";

}
$result->free();
$db->close();
?>



PHP新手。上面的php代碼中，For迴圈實現了從結果集中取出一行資料。奇怪的是當把注釋掉的代碼開啟，把運行OK的代碼注釋掉，就會出錯。出錯的地方就在於調用fetch_assoc()函數。那為什麼調用fetch_row()函數沒有呢？

