PHP日期函數date格式化UNIX時間的方法_PHP教程

PHP日期函數date格式化UNIX時間的方法

這篇文章主要介紹了PHP日期函數date格式化UNIX時間的方法,執行個體分析了php中date函數的提示,需要的朋友可以參考下

本文執行個體講述了PHP日期函數date格式化UNIX時間的方法。分享給大家供大家參考。具體分析如下：

日期函數可以根據指定的格式將一個unix時間格式化成想要的文本輸出

使用到函數文法如下

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1 2	string date (string $Format); string date (string $Format, int $Time);

下面是示範代碼

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echo "When this page was loaded,\n"; echo 'It was then ', date ('r'), "\n"; echo 'The currend date was ', date ('F j, Y'), "\n"; echo 'The currend date was ', date ('M j, Y'), "\n"; echo 'The currend date was ', date ('m/d/y'), "\n"; echo 'The currend date was the ', date ('jS \o\f M, Y'), "\n"; echo 'The currend time was ', date ('g:i:s A T'), "\n"; echo 'The currend time was ', date ('H:i:s O'), "\n"; echo date ('Y'); date ('L')?(print ' is'):(print ' is not'); echo " a leap year\n"; echo time ('U'), " seconds had elapsed since January 1, 1970.\n"; ?>

輸出結果如下

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It was then Sat, 26 Dec 2009 07:09:51 +0000 The currend date was December 26, 2009 The currend date was Dec 26, 2009 The currend date was 12/26/09 The currend date was the 26th of Dec, 2009 The currend time was 7:09:51 AM GMT The currend time was 07:09:51 +0000 2009 is not a leap year 1261811391 seconds had elapsed since January 1, 1970.

希望本文所述對大家的php程式設計有所協助。

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