PHP擷取一年有幾周以及每周開始日期和結束日期

標籤：

最近接了一個項目，其中有一需求是用php擷取一年有幾周以及每周開始日期和接觸日期。在網上找些資料沒有合適的，於是自己做了一份，下面通過兩種方式實現PHP擷取一年有幾周以及每周開始日期和結束日期

代碼一：

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<?phpheader("Content-type:text/html;charset=utf-8");date_default_timezone_set("Asia/Shanghai");$year = (int)$_GET[‘year‘];$week = (int)$_GET[‘week‘];$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));echo $year . ‘年一共有‘ . $weeks . ‘周<br />‘;if ($week > $weeks || $week <= 0){ $week = 1;}if ($week < 10){ $week = ‘0‘ . $week;}$timestamp[‘start‘] = strtotime($year . ‘W‘ . $week);$timestamp[‘end‘] = strtotime(‘+1 week -1 day‘, $timestamp[‘start‘]);echo $year . ‘年第‘ . $week . ‘周開始時間戳：‘ . $timestamp[‘start‘] . ‘<br />‘;echo $year . ‘年第‘ . $week . ‘周結束時間戳記：‘ . $timestamp[‘end‘] . ‘<br />‘;echo $year . ‘年第‘ . $week . ‘周開始日期：‘ . date("Y-m-d", $timestamp[‘start‘]) . ‘<br />‘;echo $year . ‘年第‘ . $week . ‘周結束日期：‘ . date("Y-m-d", $timestamp[‘end‘]);?>

代碼二：

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<?phpheader("Content-type:text/html;charset=utf-8");function getIsoWeeksInYear($year){ $date = new DateTime; $date->setISODate($year, 53); return ($date->format("W") === "53" ? 53 : 52);}function weekday($custom_date){ $week_start = date(‘d-m-Y‘, strtotime(‘this week monday‘, $custom_date)); $week_end = date(‘d-m-Y‘, strtotime(‘this week sunday‘, $custom_date)); $week_array[0] = $week_start; $week_array[1] = $week_end; return $week_array;}echo ‘<br> Weeks in 2013<br>‘ . getIsoWeeksInYear(2013);$weekday = weekday(strtotime(date(‘d-m-Y‘, strtotime(‘5-8-2013‘))));echo ‘<br> 10-8-2013‘;echo ‘<br>Start: ‘ . $weekday[0];echo ‘<br>End: ‘ . $weekday[1];?>

以上本文的全部內容，希望對大家學習PHP擷取一年有幾周以及每周開始日期和結束日期，有所協助。

PHP擷取一年有幾周以及每周開始日期和結束日期