PHP擷取指定時間段之間的 年,月,天,時,分,秒_php技巧

核心代碼：

Class Utils {     /** * format MySQL DateTime (YYYY-MM-DD hh:mm:ss) 把mysql中尋找出來的資料格式轉換成時間秒數 * @param string $datetime */public function fmDatetime($datetime) {  $year = substr($datetime,0,4);  $month = substr($datetime,5,2);  $day = substr($datetime,8,2);  $hour = substr($datetime,11,2);  $min = substr($datetime,14,2);  $sec = substr($datetime,17,2);  return mktime($hour,$min,$sec,$month,$day,0+$year);}/** *  * 根據倆個時間擷取倆個時間的 包含的 年，月數，天數，小時，分鐘，秒 * @param String $start * @param String $end * @return ArrayObject  */ private function diffDateTime($DateStart,$DateEnd){$rs = array();$sYear = substr($DateStart,0,4);$eYear = substr($DateEnd,0,4);$sMonth = substr($DateStart,5,2);$eMonth = substr($DateEnd,5,2);$sDay = substr($DateStart,8,2);$eDay = substr($DateEnd,8,2);$startTime = $this->fmDatetime($DateStart);$endTime = $this->fmDatetime($DateEnd);$dis = $endTime-$startTime;//得到倆個時間的秒數$d = ceil($dis/(24*60*60));//得到天數$rs['day'] = $d;//天數$rs['hour'] = ceil($dis/(60*60));//小時$rs['minute'] = ceil($dis/60);//分鐘$rs['second'] = $dis;//秒數$rs['week'] = ceil($d/7);//周$tem = ($eYear-$sYear)*12;//月份$tem1 = $eYear-$sYear;//年if($eMonth-$sMonth<0){//月份相減為負$tem +=($eMonth-$sMonth);}else if($eMonth==$sMonth){//月份相同if($eDay-$sDay>=0){$tem ++;$tem1++;}}else if($eMonth-$sMonth>0){//月份相減正負$tem1++;if($eDay-$sDay>=0){//且日期相減為正數$tem +=($eMonth-$sMonth)+1;}else{$tem +=($eMonth-$sMonth);}}$rs['month'] = $tem;$rs['year'] = $tem1;return $rs;}}

一年多一天，返回的是2年，一個月多一天返回的是2個月，以此推......項目需要，才做此出來，開始我也到網上找這樣的例子，但大家都是把年就按365天來算，月就按30天來算，這樣算出來的結果肯定是沒用的，年有可能是366天，月有可能是31，29，28都有可能