php擷取通過url的json資料，返回的是空值

http://php.net/api/apply.php?&apply={"apply":{"name":"4747474","site":"http:\/\/4444444444444444","icon":"47","information":"474","about":"747","weibo":"74444444444","email":"74444444444444444","moblie":"89742589633","isfree":"y","applytime":1349939108}}

這個是一個連結，我在這個頁面上要怎麼把那段json格式給接下出來呢？

回複討論(解決方案)

$x = json_decode($_GET['apply']);

$x = json_decode($_GET['apply']);

得出來還是空值，可能那個字串存在錯誤吧...

var_dump(json_decode($_GET['apply'],true));
看?出什麽？

var_dump(json_decode($_GET['apply'],true));
看?出什麽？

NULL

var_dump(json_decode(urldecode($_GET['apply']),true));

var_dump(json_decode(urldecode($_GET['apply']),true));

也是不行，最後我把那些多餘的\去掉了，不知道是為啥啊？

print_r(json_decode('{"apply":{"name":"4747474","site":"http:\/\/4444444444444444","icon":"47","information":"474","about":"747","weibo":"74444444444","email":"74444444444444444","moblie":"89742589633","isfree":"y","applytime":1349939108}}'));

stdClass Object(    [apply] => stdClass Object        (            [name] => 4747474            [site] => http://4444444444444444            [icon] => 47            [information] => 474            [about] => 747            [weibo] => 74444444444            [email] => 74444444444444444            [moblie] => 89742589633            [isfree] => y            [applytime] => 1349939108        ))

PHP code
print_r(json_decode('{"apply":{"name":"4747474","site":"http:\/\/4444444444444444","icon":"47","information":"474","about":"747","weibo":"74444444444","email":"74444444444444444","moblie":"……

嗯，謝謝了

LZ地址中參數apply前面多了個&符號，你看會不會是這個的問題

之前是我的文字格式設定有問題，得出來的結果有錯誤

$json_string = $_GET["apply"];
if(ini_get("magic_quotes_gpc")=="1")
{
$json_string=stripslashes($json_string);
}

