PHP組指標賦值問題

來源:互聯網
上載者:User
$arr=array();$arr['imagePath']="";$arr['Size1']="";$arr['imageaPath']="";$arr['image2Path']="";$arr['Size33']="";$arr['image5Path']="";$arr['Size55']="";$arr['imagebbPath']="";$arr['imageccPath']="";$arr['Size555']="";$arr['imageqqPath']="";$arr['image99Path']="";$arr['imageeePath']="";$arr['imagepPath']="";$arr['Size66']="";$url='/';$arr['imagePath']=$url;$arr['imageaPath']=$url;$arr['image2Path']=$url;$arr['image5Path']=$url;$arr['imagebbPath']=$url;$arr['imageccPath']=$url;$arr['imageqqPath']=$url;$arr['image99Path']=$url;$arr['imageeePath']=$url;$arr['imagepPath']=$url;


回複討論(解決方案)

樓主的問題是?

$arr=array();$arr['imagePath']="";$arr['Size1']="";$arr['imageaPath']="";$arr['image2Path']="";$arr['Size33']="";$arr['image5Path']="";$arr['Size55']="";$arr['imagebbPath']="";$arr['imageccPath']="";$arr['Size555']="";$arr['imageqqPath']="";$arr['image99Path']="";$arr['imageeePath']="";$arr['imagepPath']="";$arr['Size66']="";$url='/';$arr['imagePath']=$url;$arr['imageaPath']=$url;$arr['image2Path']=$url;$arr['image5Path']=$url;$arr['imagebbPath']=$url;$arr['imageccPath']=$url;$arr['imageqqPath']=$url;$arr['image99Path']=$url;$arr['imageeePath']=$url;$arr['imagepPath']=$url;



這種賦值方法好像有點怪怪的

樓主的問題是?



這種賦值方法好像有點怪怪的

$url='/';
$arr['imagePath']=$url;
$arr['imageaPath']=$url;
$arr['image2Path']=$url;
$arr['image5Path']=$url;
$arr['imagebbPath']=$url;
$arr['imageccPath']=$url;
$arr['imageqqPath']=$url;
$arr['image99Path']=$url;
$arr['imageeePath']=$url;
$arr['imagepPath']=$url;

這有什麼“怪”呢?
看上去也還算清晰明了

foreach($ar as $k=?&$v) if(substr($k, -4) == 'Path') $v = $url;

這有什麼“怪”呢?
看上去也還算清晰明了

foreach($ar as $k=?&$v) if(substr($k, -4) == 'Path') $v = $url;


請教
$k= ?&$v ??

$k=>&$v
不好意思,按錯了鍵

$k=>&$v
不好意思,按錯了鍵


地址引用,我咋沒想到!!!!! 好辦法啊!

不引用也是一樣的

foreach($ar as $k=>$v) if(substr($k, -4) == 'Path') $ar[$k] = $url;

$val){    if(substr($key,0,5)=='image'){        $arr[$key] = $url;    }}print_r($arr);?>
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