PHP實現Javascript的escape(),unescape()的方法

來源:互聯網
上載者:User
javascript

最完整的phpescape函數

function phpescape($str){
    preg_match_all("/[\x80-\xff].|[\x01-\x7f]+/",$str,$newstr);
    $ar = $newstr[0];
    foreach($ar as $k=>$v){
        if(ord($ar[$k])>=127){
            $tmpString=bin2hex(iconv("GBK","ucs-2",$v));
            if (!eregi("WIN",PHP_OS)){
                $tmpString = substr($tmpString,2,2).substr($tmpString,0,2);
            }
            $reString.="%u".$tmpString;
        } else {
            $reString.= rawurlencode($v);
        }
    }
    return $reString;
}
 

//該方法在某些linux系統下,
//會因為iconv的php版本問題
//造成該函數方法無法正常使用
//使用前請測試先
function phpescape($str) {
  preg_match_all("/[€-ÿ].|[-]+/",$str,$r);
  $ar = $r[0];
  foreach($ar as $k=>$v) {
    if(ord($v[0]) < 128){
      $ar[$k] = rawurlencode($v);
      echo $ar[$k]."<BR>";
    }
    else {
      $ar[$k] = "%u".bin2hex(iconv("GBK","ISO-10646-UCS-2",$v));     //此處GBK為目標代碼的編碼格式,請實際情況修改
      echo $ar[$k]."<BR>";
    }
  }
  return join("",$ar);
}

//該方法為上面的改進版
//首先判斷平台版本是否為win系統
//但該版本會有些特殊字元無法使用
function phpescape($str){
    $sublen=strlen($str);
    $reString="";
    for ($i=0;$i<$sublen;$i++){
        if(ord($str[$i])>=127){
            $tmpString=bin2hex(iconv("GBK","ucs-2",substr($str,$i,2)));    //此處GBK為目標代碼的編碼格式,請實際情況修改

            if (!eregi("WIN",PHP_OS)){
                $tmpString=substr($tmpString,2,2).substr($tmpString,0,2);
            }
            $reString.="%u".$tmpString;
            $i++;
        } else {
            $reString.="%".dechex(ord($str[$i]));
        }
    }
    return $reString;
}


function unescape($str) {
         $str = rawurldecode($str);
         preg_match_all("/%u.{4}|&#x.{4};|&#d+;|.+/U",$str,$r);
         $ar = $r[0];
         foreach($ar as $k=>$v) {
                  if(substr($v,0,2) == "%u")
                           $ar[$k] = iconv("UCS-2","GBK",pack("H4",substr($v,-4)));
                  elseif(substr($v,0,3) == "&#x")
                           $ar[$k] = iconv("UCS-2","GBK",pack("H4",substr($v,3,-1)));
                  elseif(substr($v,0,2) == "&#") {
                           $ar[$k] = iconv("UCS-2","GBK",pack("n",substr($v,2,-1)));
                  }
         }
         return join("",$ar);
}



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