本文執行個體講述了PHP實現上傳圖片到資料庫並顯示輸出的方法。分享給大家供大家參考，具體如下：
1. 建立資料表
CREATE TABLE ccs_image ( id int(4) unsigned NOT NULL auto_increment, description varchar(250) default NULL, bin_data longblob, filename varchar(50) default NULL, filesize varchar(50) default NULL, filetype varchar(50) default NULL, PRIMARY KEY (id))engine=myisam DEFAULT charset=utf8
2. 用於上傳圖片到伺服器的頁面 upimage.html
<!doctype html><html lang="en"><head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0"> <meta http-equiv="X-UA-Compatible" content="ie=edge"> <style type="text/css"> *{margin: 1%} </style> <title>Document</title></head><body><form method="post" action="upimage.php" enctype="multipart/form-data"> 描述: <input type="text" name="form_description" size="40"> <input type="hidden" name="MAX_FILE_SIZE" value="1000000"> <br> 上傳檔案到資料庫: <input type="file" name="form_data" size="40"><br> <input type="submit" name="submit" value="submit"></form></body></html>
3. 處理圖片上傳的php upimage.php
<?phpif (isset($_POST['submit'])) { $form_description = $_POST['form_description']; $form_data_name = $_FILES['form_data']['name']; $form_data_size = $_FILES['form_data']['size']; $form_data_type = $_FILES['form_data']['type']; $form_data = $_FILES['form_data']['tmp_name']; $dsn = 'mysql:dbname=test;host=localhost'; $pdo = new PDO($dsn, 'root', 'root'); $data = addslashes(fread(fopen($form_data, "r"), filesize($form_data))); //echo "mysqlPicture=".$data; $result = $pdo->query("INSERT INTO ccs_image (description,bin_data,filename,filesize,filetype) VALUES ('$form_description','$data','$form_data_name','$form_data_size','$form_data_type')"); if ($result) { echo "圖片已儲存到資料庫"; } else { echo "請求失敗,請重試";
注:圖片是以二進位blob形式存進資料庫的,像這樣
4. 顯示圖片的php getimage.php
<?php $id =2;// $_GET['id']; 為簡潔,直接將id寫上了,正常應該是通過使用者填入的id擷取的 $dsn='mysql:dbname=test;host=localhost'; $pdo=new PDO($dsn,'root','root'); $query = "select bin_data,filetype from ccs_image where id=2"; $result = $pdo->query($query); $result=$result->fetchAll(2);// var_dump($result); $data = $result[0]['bin_data']; $type = $result[0]['filetype']; Header( "Content-type: $type"); echo $data;
到瀏覽器查看已經上傳的圖片,看是否可以顯示
是沒有問題的,證明圖片已經以二進位的形式儲存到資料庫了
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