php實現統計網站線上人數的方法_PHP

本文執行個體講述了php實現統計網站線上人數的方法。分享給大家供大家參考。具體實現方法如下：

<?phpfunction getIpAddress() { // 取得目前使用者的IP地址 if (getenv('HTTP_CLIENT_IP')) { $ip = getenv('HTTP_CLIENT_IP'); } elseif (getenv('HTTP_X_FORWARDED_FOR')) { $ip = getenv('HTTP_X_FORWARDED_FOR'); } elseif (getenv('REMOTE_ADDR')) { $ip = getenv('REMOTE_ADDR'); } else { $ip = $_SERVER['REMOE_ADDR']; }  return $ip;} function writeover($filename,$data,$method = 'w',$chmod = 0){ $handle = fopen($filename, $method); !handle && die("檔案開啟失敗"); flock($handle, LOCK_EX); fwrite($handle, $data); flock($handle, LOCK_UN); fclose($handle); $chmod && @chmod($filename, 0777);} function count_online_num($time, $ip) { $fileCount = './count.txt'; $count = 0; $gap = 900; //15分鐘不重新整理頁面就 if (!file_exists($fileCount)) { $str = $time . "\t" . $ip . "\r\n"; writeover($fileCount, $str, 'w', 1); $count = 1; } else { $arr = file($fileCount); $flag = 0; foreach($arr as $key => $val) {  $val= trim($val);  if ($val != "") {  list($when, $seti) = explode("\t", $val);  if ($seti ==$ip) {   $arr[$key] = $time . "\t" . $seti;   $flag = 1;  } else {   $currentTime = time();   if ($currentTime - $when > 900) {   unset($arr[$key]);   }else{   $arr[$key]=$val;   }  }   }  }  if ($flag == 0) {  array_push($arr, $time . "\t" . $ip); }  $count = count($arr); $str = implode("\r\n", $arr); $str.="\r\n"; writeover($fileCount, $str, 'w', 0); unset($arr); }  return $count;} $time = time();$ip = getIpAddress();$online_num = count_online_num($time,$ip);echo $online_num;?>

希望本文所述對大家的php程式設計有所協助。

