phpRegex匹配URL中的網域名稱

$search = '~^(([^:/?#]+):)?(//([^/?#]*))?([^?#]*)(\?([^#]*))?(#(.*))?~i'; $url = 'http://www.php.net/pub/ietf/uri/#Related'; $url = trim($url); preg_match_all($search, $url ,$rr); printf(" 輸出URL資料為： %s \n",var_export( $rr ,TRUE)); /* 各分組如下 $1 = http: $2 = http $3 = //www.php.net $4 = www.php.net $5 = /pub/ietf/uri/ $6 = $7 = $8 = #Related $9 = Related */ ?> 複製代碼 這裡提供另一個簡潔的代碼： // 從 URL 中取得主機名稱 preg_match("/^(http:\/\/)?([^\/]+)/i", "http：//www.php.net/index.html", $matches); $host = $matches[2]; // 從主機名稱中取得後面兩段 preg_match("/[^\.\/]+\.[^\.\/]+$/", $host, $matches); echo "domain name is: {$matches[0]}\n"; ?> 複製代碼 執行後輸出：domain name is: php.net

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