php 正則字串

來源:互聯網
上載者:User
下面是字串

$a = '../post/luoji/soft/aaa.chm’
$b = '../post/luoji/bbb.txt'
$c = ' post/luoji/c.rar'
$d = ’../../luo/p/d.zip‘
$e = ‘../../lio/p/p/p/p/p/p/p/p/a.tar.gz’
$f = ‘../pp/tt/p/p/p/lp/p/tttt/p/t.rpm’

要求擷取成這樣:

$a = 'aaa.chm‘
$b = 'bbb.txt'
$c = ' c.rar'
$d = ’d.zip‘
$e = ‘a.tar.gz’
$f = ‘t.rpm’


就是不管字串有多長只要擷取最後的名稱

我只會這樣寫

$str = "../post/luoji/aaa.chm";
$str = preg_split("/[\s,\/!]+/", $str);
echo '
';print_r($str[3]);  

不能動態擷取

怎麼用正則擷取?謝謝!


回複討論(解決方案)

$a = '../post/luoji/soft/aaa.chm';$a=pathinfo($a,PATHINFO_BASENAME);echo $a;

$str = "../post/luoji/aaa.chm";
$str = preg_split("/[\s,\/!]+/", $str);
$len=sizeof($str);
$res=$str[$len-1];
echo $res;

$a = '../post/luoji/soft/aaa.chm';preg_match('#[^/]+$#', $a, $r);echo $r[0];
$a = '../post/luoji/soft/aaa.chm';$a = preg_split('#/#', $a);echo array_pop($a);
$a = '../post/luoji/soft/aaa.chm';$a = preg_split('#/#', $a);echo end($a);
$a = '../post/luoji/soft/aaa.chm';echo basename($a);
......
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