php判斷正常訪問和外部存取的樣本_PHP教程

php判斷正常訪問和外部存取
複製代碼 代碼如下:
session_start();
if(isset($_POST['check'])&&!empty($_POST['name'])){
if($_POST['check'] == $_SESSION['check']){
echo "正常訪問";
}else{
echo "外部存取";
}
}
$token = md5(uniqid(rand(),true));
$_SESSION['check'] = $token;
?>

http://www.bkjia.com/PHPjc/732388.htmlwww.bkjia.comtruehttp://www.bkjia.com/PHPjc/732388.htmlTechArticlephp判斷正常訪問和外部存取 複製代碼 代碼如下: ?php session_start(); if(isset($_POST['check'])!empty($_POST['name'])){ if($_POST['check'] == $_SESSION['check']){ ec...

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