php 類型判斷

來源:互聯網
上載者:User

學習筆記

 

<?
//判斷數組
$colors = array("red", "blue", "green");
if(is_array($colors)) {
    echo("colors is an array"."<br>");
}
//雙精確度數判斷
$Temperature = 15.23;
if(is_double($Temperature)) {
    echo("$Temperature is a double"."<br>");
}
//整數判斷
$PageCount = 2234;
if(is_integer($PageCount)) {
    echo("$PageCount is an integer"."<br>");
}
//對象判斷
class widget {
    var $name;
    var $length;
}
$thing = new widget;

if(is_object($thing)) {
    echo("thing is an object"."<br>");
}
//字元判斷
$Greeting = "Hello";
if(is_string($Greeting)) {
    echo("$Greeting is a string"."<br>");
}
//數字判斷
$Num=1002;
if(is_int($Num)){
    echo("$Num is a int"."<br>");
}
?>

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