php上傳視頻的代碼_PHP教程

來源:互聯網
上載者:User

網頁教學網(webjx.com)檔案上傳執行個體


upfile.php.

function getname($exname){

$dir = "./uploadfile/";

$i=1;

if(!is_dir($dir)){

mkdir($dir,0777);

}


while(true){

if(!is_file($dir.$i.".".$exname)){

$name=$i.".".$exname;

break;

}

$i++;

}


return $dir.$name;

}


$exname=strtolower(substr($_FILES['upfile']['name'],(strrpos($_FILES['upfile']['name'],'.')+1)));

$uploadfile = getname($exname);


if (move_uploaded_file($_FILES['upfile']['tmp_name'], $uploadfile)) {

echo "

檔案上傳成功!



";

}else {

echo "

檔案上傳失敗!



";

} echo "下面是檔案上傳的一些資訊:

原檔案名稱:".$_FILES['upfile']['name'] ."

類型:" .$_FILES['upfile']['type'] ."

臨時檔案名稱:".$_FILES['upfile']['tmp_name']. "

檔案大小:".$_FILES['upfile']['size']."

錯誤碼:".$_FILES['upfile']['error'];
?>

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