題意:輸入N(0<=N<=1,000,000 )個長度為M(M<=30 )的字串,字典序輸出每種字串出現個數。
分析:這裡採用兩種方法,一種是qsort,還有一種BST。
C++源碼:
qsort:
#include <stdio.h><br />#include <string.h><br />#include <stdlib.h></p><p>const int M = 1000000;<br />const int N = 36;<br />char s[M+1][N];<br />int comp(const void *a, const void *b){<br /> return strcmp((char*)a,(char*)b);<br />}<br />int main()<br />{<br /> int i,j;<br /> char c;<br /> i=j=0;<br /> while((c=getchar())!=EOF){<br /> if(c!='/n')<br /> s[i][j++]=c;<br /> else{<br /> s[i][j]='/0';<br /> i++;<br /> j=0;<br /> }</p><p> }<br /> qsort(s,i,sizeof(s[0]),comp);<br /> if(i>1){<br /> int count=1;<br /> char tmp[N];<br /> strcpy(tmp,s[0]);<br /> for(j=1;j<i;j++){<br /> if(!strcmp(s[j],tmp)){<br /> count++;<br /> }else{<br /> printf("%s %.4f/n",tmp,count*100.0/i);<br /> strcpy(tmp,s[j]);<br /> count=1;<br /> }<br /> }<br /> printf("%s %.4f/n", tmp,count*100.0/i);<br /> }<br /> return 0;<br />}<br />
BST:
#include <cstdio><br />#include <cstring></p><p>const int M = 32;<br />struct node{<br /> node(char *s):t(1),left(NULL),right(NULL){<br /> strcpy(str,s);<br /> }<br /> char str[M];<br /> int t;<br /> node *left, *right;<br />};<br />node* insert(node* r, char *s){<br /> if(r==NULL){<br /> r = new node(s);<br /> }else{<br /> int ans = strcmp(r->str,s);<br /> if(ans == 0)<br /> r->t++;<br /> else if(ans==1)<br /> r->left = insert(r->left,s);<br /> else<br /> r->right = insert(r->right,s);<br /> }<br /> return r;<br />}<br />void inorder(node* r,int n){<br /> if(r!=NULL){<br /> inorder(r->left,n);<br /> printf("%s %.4f/n", r->str, r->t*100.0/n);<br /> inorder(r->right,n);<br /> }<br />}<br />int main()<br />{<br /> int num=0;<br /> char s[M];<br /> node* root=NULL;<br /> while(gets(s)!=NULL){<br /> root=insert(root,s);<br /> num++;<br /> }<br /> inorder(root,num);<br /> return 0;<br />}<br />