POJ 3630 字典樹 判斷單詞是否不覆蓋

題意：

若有單詞覆蓋輸出NO

否則輸出YES

 

字典樹裸題，判斷建立單詞時 路徑中是否存在 單詞結尾

 

 

#include<iostream>      #include<stdio.h>      #include<string>      #include<string.h>      #include<algorithm>      #include<set>      #include <cstdio>        #include <cstring>        #include <iostream>        #include <math.h>        #include <queue>        #define ll intusing namespace std;      inline ll Min(ll a,ll b){return a>b?b:a;}    inline ll Max(ll a,ll b){return a>b?a:b;}    #define Word_Len 1000000#define Sigma_size 11int ch[Word_Len][Sigma_size]; //Word_Len是字典樹的節點數 若都是小寫字母Sigma_size=26int Have_word[Word_Len]; //這個節點下有幾個單詞int val[Word_Len]; // 這個節點附帶的資訊，初始化為0表示這個節點不存在單詞，所以節點帶的資訊必須!=0int sz ; //當前節點數//初始化字典樹void init(){ sz = 1; memset(ch[0], 0, sizeof(ch[0])); memset(val, 0, sizeof(val));memset(Have_word, 0, sizeof(Have_word));}//初始化int idx(char c){ return c-'0';} //字串編號bool Creat(char *s){bool Have_creat=false; //是否建立了int u = 0, len = strlen(s);for(int i = 0; i < len; i++){int c = idx(s[i]);if(!ch[u][c]){     //節點不存在memset(ch[sz], 0, sizeof(ch[sz]));ch[u][c] = sz++;Have_creat = true;}if(Have_word[u]==1)return false;u = ch[u][c];}if(Have_word[u]==1)return false;Have_word[u]=1;return Have_creat;}char S[15];int n;int main(){int T;scanf("%d",&T);while(T--){init();int n;scanf("%d",&n);bool su=true;while(n--){scanf("%s",S);if(su)su = Creat(S);}if(su)printf("YES\n");else printf("NO\n");}return 0;}/*99211221212123412343123456812365486421344431456212354699152222323666ans:nnnyn*//*#include<iostream>#include<stdio.h>#include<string.h>#include<string>#include<algorithm>using namespace std;char s[100010][11];struct node{       int cnt;       struct node *next[11];       void init(){memset(next,0,sizeof(next));}};node a[1000000];struct node *root;int indexx=0;struct node *build(){       a[indexx].cnt=1;       a[indexx].init();       return &a[indexx++];}void save(char *s){       int len=strlen(s);       struct node *p;       p=root;       for(int i=0;i<len;i++)       {              if(p->next[s[i]-'0']!=NULL)p->next[s[i]-'0']->cnt++;              else p->next[s[i]-'0']=build();              p=p->next[s[i]-'0'];       }}int search(char *s){       int len=strlen(s);       struct node *p;       p=root;       for(int i=0;i<len;i++)       {              if(p->next[s[i]-'0']->cnt==1)return 1;              p=p->next[s[i]-'0'];       }       return 0;}char str[40000][11];int main(){       int i,j,k,m,n,T;       scanf("%d",&T);       while(T--)       {              scanf("%d",&n);              indexx=0;              root=build();              for(i=0;i<n;i++)              {                     scanf("%s",str[i]);                     save(str[i]);              }              int flag=1;              for(i=0;i<n;i++)if(search(str[i])==0)              {                     flag=0;                     break;              }              if(flag)puts("YES");              else puts("NO");       }       return 0;}*/