輸出數組給js用的有關問題

輸出數組給js用的問題

 data = [{
y: 100,
color: colors[0],
drilldown: {
name: 'MSIE versions',
categories: ['MSIE 6.0', 'MSIE 7.0', 'MSIE 8.0', 'MSIE 9.0'],
data: [10.85, 7.35, 33.06, 2.81],
color: colors[0]
}
}, {
y: 21.63,
color: colors[1],
drilldown: {
name: 'Firefox versions',
categories: ['Firefox 2.0', 'Firefox 3.0', 'Firefox 3.5', 'Firefox 3.6', 'Firefox 4.0'],
data: [0.20, 0.83, 1.58, 13.12, 5.43],
color: colors[1]
}
}, {
y: 11.94,
color: colors[2],
drilldown: {
name: 'Chrome versions',
categories: ['Chrome 5.0', 'Chrome 6.0', 'Chrome 7.0', 'Chrome 8.0', 'Chrome 9.0',
'Chrome 10.0', 'Chrome 11.0', 'Chrome 12.0'],
data: [0.12, 0.19, 0.12, 0.36, 0.32, 9.91, 0.50, 0.22],
color: colors[2]
}
}, {
y: 7.15,
color: colors[3],
drilldown: {
name: 'Safari versions',
categories: ['Safari 5.0', 'Safari 4.0', 'Safari Win 5.0', 'Safari 4.1', 'Safari/Maxthon',
'Safari 3.1', 'Safari 4.1'],
data: [4.55, 1.42, 0.23, 0.21, 0.20, 0.19, 0.14],
color: colors[3]
}
}, {
y: 2.14,
color: colors[4],
drilldown: {
name: 'Opera versions',
categories: ['Opera 9.x', 'Opera 10.x', 'Opera 11.x'],
data: [ 0.12, 0.37, 1.65],
color: colors[4]
}
}]; 

以上是javascript原本的數組

data = [{"y":673,"color":"colors[0]","drilldown":{"name":"AMZ_AC \u660e\u7ec6","categories":["DE","ES","FR","GB","IT"],"data":["28","2","410","211","22"],"color":"colors[0]"}},{"y":290,"color":"colors[1]","drilldown":{"name":"AM_AC \u660e\u7ec6","categories":["JP"],"data":["290"],"color":"colors[1]"}},{"y":222,"color":"colors[2]","drilldown":{"name":"CO_AC \u660e\u7ec6","categories":["JP"],"data":["222"],"color":"colors[2]"}}];

以上是我用PHP輸出的數組

請問這兩個哪裡不一樣啊？？輸出產生的結果跟原來的結果差好遠

分享到：

------解決方案--------------------
是的，preg_replace是屬於比較暴力的方法
但是你的 colors 是 js 的數組，php 又不可能知道。只能當做字串處理了

