Python - 按天算年齡

標籤：pass   python   body   bst   alc   gpo   rect   技術   isp   

問題：輸入出生日期和當前的日期，輸出活了多少天

舉例：你是昨天出生的，那麼輸出就為1

分三種情況討論：

1、年份和月份都相同

2、年份相同月份不同，先計算出生當天是當年的第幾天，後計算當前為當年的第幾天，相減

3、年份不同，還是先計算出生當天為當年的第幾天，後計算當前為當年的第幾天，做閏年判斷，逐一相加

閏年為一下兩種情況

1、能被400整除

2、能被4整除但不能被100整除

 

、、、、、、、、、、、、、、、

 

本題來自Udacity的電腦科學導論課程，用來做Python入門

Python語言兼具一般進階語言和指令碼語言的特點，在官網下了一個東東，只會做指令碼，函數現在只會一行一行往裡敲，然後運行，無法調試，好像是需要找一個開發環境，有空弄

附代碼

# By Websten from forums## Given your birthday and the current date, calculate your age in days. # Account for leap days. ## Assume that the birthday and current date are correct dates (and no # time travel). #def is_leap(year):    result = False    if year % 400 == 0:        result = True    if year % 4 == 0 and year % 100 != 0:        result = True    return resultdef daysBetweenDates(year1, month1, day1, year2, month2, day2):    daysOfMonths = [ 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]    if year1 == year2 and month1 == month2:        days = day2 - day1    if year1 == year2:        days1 = 0        i = 0        while i < month1 - 1:            days1 = days1 + daysOfMonths[i]            i = i + 1        days1 = days1 + day1        if is_leap(year1) and month1 > 2:            days1 = days1 + 1        days2 = 0        i = 0        while i < month2 - 1:            days2 = days2 + daysOfMonths[i]            i = i + 1        days2 = days2 + day2        if is_leap(year2) and month2 > 2:            days2 = days2 + 1        days = days2 - days1    else:        days1 = 0        i = 0        while i < month1 - 1:            days1 = days1 + daysOfMonths[i]            i = i + 1        days1 = days1 + day1        if is_leap(year1) and month1 > 2:            days1 = days1 + 1        days2 = 0        i = 0        while i < month2 - 1:            days2 = days2 + daysOfMonths[i]            i = i + 1        days2 = days2 + day2        if is_leap(year2) and month2 > 2:            days2 = days2 + 1        days = 365 - days1 + days2        if is_leap(year1):            days = days + 1        year1 = year1 + 1        while year1 < year2:            days = days + 365            year1 = year1 + 1            if is_leap(year1):                days = days + 1    return days                        # Test routinedef test():    test_cases = [((2012,1,1,2012,2,28), 58),                   ((2012,1,1,2012,3,1), 60),                  ((2011,6,30,2012,6,30), 366),                  ((2011,1,1,2012,8,8), 585 ),                  ((1900,1,1,1999,12,31), 36523)]    for (args, answer) in test_cases:        result = daysBetweenDates(*args)        if result != answer:            print "Test with data:", args, "failed"        else:            print "Test case passed!"test()

View Code

 

Python - 按天算年齡