python API url 級聯產生

標籤：

參考了一下公司 python 達人 rpc 介面級聯 api 調用

rpc.api.users.list()

rpc.api.login(username=‘‘,password=‘‘)

rpc[‘api/users‘](id=222)

寫了一個 demo，python 確實很簡潔，不到 30 行代碼搞定

# coding=utf-8class NameChain(object):    def __init__(self,prefix,callback):        self._prefix = prefix        self._callback = callback    def __getattr__(self,item):        next_prefix = self._prefix + ‘/‘ + item        return NameChain(next_prefix,self._callback)    def __call__(self,**kw):        self._callback(self._prefix,kw)    def __getitem__(self,item):        self._prefix = item        return selfclass Service(object):    def __init__(self):        self._api = NameChain(‘api‘,self._invoke)    def _invoke(self,method,params):        print ‘******************‘        print ‘invoke method:‘,method        if len(params) ==0:            print ‘params is empty‘            return        print ‘params is‘        for k,v in params.iteritems():            print k,‘:‘,v    @property     def api(self):         return self._apis = Service()api = s.api# 調用方式一print ‘調用方式一‘# api/usersapi.users()   # api/user    params {"id",111,"name":"leslie"}api.user(id=111,name=‘leslie‘)# pai/user/tags api.user.tags()  #api/user/tags/list params {"id",111,"session_id","love you forever"}api.user.tags.list(id=111,session_id=‘love you forever‘)# 調用方式二print ‘調用方式二‘api[‘api/users‘]()api[‘api/users‘](id=111,name=‘leslie‘)api[‘api/user/tags‘]()api[‘api/user/tags/list‘](id=111,session_id=‘love you forever‘)

 

python API url 級聯產生