python開發之基於thread線程搜尋本地檔案的方法

本文執行個體講述了python開發之基於thread線程搜尋本地檔案的方法。分享給大家供大家參考，具體如下：

先來看看運行：

利用多個線程處理搜尋的問題，我們可以發現他很快....

下面是代碼部分：

# A parallelized "find(1)" using the thread module.# This demonstrates the use of a work queue and worker threads.# It really does do more stats/sec when using multiple threads,# although the improvement is only about 20-30 percent.# (That was 8 years ago. In 2002, on Linux, I can't measure# a speedup. :-( )# I'm too lazy to write a command line parser for the full find(1)# command line syntax, so the predicate it searches for is wired-in,# see function selector() below. (It currently searches for files with# world write permission.)# Usage: parfind.py [-w nworkers] [directory] ...# Default nworkers is 4import sysimport getoptimport timeimport osfrom stat import *import _thread as thread# Work queue class. Usage:#  wq = WorkQ()#  wq.addwork(func, (arg1, arg2, ...)) # one or more calls#  wq.run(nworkers)# The work is done when wq.run() completes.# The function calls executed by the workers may add more work.# Don't use keyboard interrupts!class WorkQ:  # Invariants:  # - busy and work are only modified when mutex is locked  # - len(work) is the number of jobs ready to be taken  # - busy is the number of jobs being done  # - todo is locked iff there is no work and somebody is busy  def __init__(self):    self.mutex = thread.allocate()    self.todo = thread.allocate()    self.todo.acquire()    self.work = []    self.busy = 0  def addwork(self, func, args):    job = (func, args)    self.mutex.acquire()    self.work.append(job)    self.mutex.release()    if len(self.work) == 1:      self.todo.release()  def _getwork(self):    self.todo.acquire()    self.mutex.acquire()    if self.busy == 0 and len(self.work) == 0:      self.mutex.release()      self.todo.release()      return None    job = self.work[0]    del self.work[0]    self.busy = self.busy + 1    self.mutex.release()    if len(self.work) > 0:      self.todo.release()    return job  def _donework(self):    self.mutex.acquire()    self.busy = self.busy - 1    if self.busy == 0 and len(self.work) == 0:      self.todo.release()    self.mutex.release()  def _worker(self):    time.sleep(0.00001)   # Let other threads run    while 1:      job = self._getwork()      if not job:        break      func, args = job      func(*args)      self._donework()  def run(self, nworkers):    if not self.work:      return # Nothing to do    for i in range(nworkers-1):      thread.start_new(self._worker, ())    self._worker()    self.todo.acquire()# Main programdef main():  nworkers = 4  #print(getopt.getopt(sys.argv[1:], '-w:'))  opts, args = getopt.getopt(sys.argv[1:], '-w:')  for opt, arg in opts:    if opt == '-w':      nworkers = int(arg)  if not args:    #print(os.curdir)    args = [os.curdir]  wq = WorkQ()  for dir in args:    wq.addwork(find, (dir, selector, wq))  t1 = time.time()  wq.run(nworkers)  t2 = time.time()  sys.stderr.write('Total time %r sec.\n' % (t2-t1))# The predicate -- defines what files we look for.# Feel free to change this to suit your purposedef selector(dir, name, fullname, stat):  # Look for world writable files that are not symlinks  return (stat[ST_MODE] & 0o002) != 0 and not S_ISLNK(stat[ST_MODE])# The find procedure -- calls wq.addwork() for subdirectoriesdef find(dir, pred, wq):  try:    names = os.listdir(dir)  except os.error as msg:    print(repr(dir), ':', msg)    return  for name in names:    if name not in (os.curdir, os.pardir):      fullname = os.path.join(dir, name)      try:        stat = os.lstat(fullname)      except os.error as msg:        print(repr(fullname), ':', msg)        continue      if pred(dir, name, fullname, stat):        print(fullname)      if S_ISDIR(stat[ST_MODE]):        if not os.path.ismount(fullname):          wq.addwork(find, (fullname, pred, wq))# Call the main programmain()

希望本文所述對大家Python程式設計有所協助。

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