Python執行個體 — 收發郵件

Python執行個體 -- 收發郵件
2012-09-12 20:17:49

分類： LINUX

python發郵件

1. #!/usr/bin/env python3
   
2. #coding: utf-8
   
3. import smtplib
4. from email.mime.text
   import MIMEText
5. from email.header
   import Header
6.   
7. sender = '***'
   
8. receiver = '***'
   
9. subject = 'python email test'
   
10. smtpserver = 'smtp.163.com'
    
11. username = '***'
    
12. password = '***'
    
13.   
14. msg = MIMEText('你好','plain','utf-8')#中文需參數‘utf-8’，單位元組字元不需要
    
15. msg['Subject']
    = Header(subject,
    'utf-8')
16.   
17. smtp = smtplib.SMTP()
    
18. smtp.connect('smtp.163.com')
    
19. smtp.login(username, password)
    
20. smtp.sendmail(sender, receiver, msg.as_string())
    
21. smtp.quit()

python收郵件

1. #!/usr/bin/env
   python3 
2. # -*- coding: utf-8
   -*-
   
3.       
4.     import poplib
5.     from email
   import parser
6.       
7.     host = 'pop.gmail.com'
   
8.     username =
   'mine@gmail.com'
9.     password =
   '*******'
10.       
11.     pop_conn = poplib.POP3_SSL(host)
    
12.     pop_conn.user(username)
    
13.     pop_conn.pass_(password)
    
14.       
15.     #Get messages from server:
    
16.     messages =
    [pop_conn.retr(i)
    for i in range(1, len(pop_conn.list()[1])
    + 1)]
    
17.       
18.     # Concat message pieces:
19.     messages =
    ["\n".join(mssg[1])
    for mssg in messages]
    
20.       
21.     #Parse message intom an email object:
22.     messages =
    [parser.Parser().parsestr(mssg)
    for mssg in messages]
    
23.     for message
    in messages:
24.         print message['Subject']
    
25.     pop_conn.quit()