python 按照list中的dic的某key排序

標籤：

面試題之一。

s=[
{"name":"Axx","score":"90"},
{"name":"Bxx","score":"91"},
{"name":"Cxx","score":"20"},
]

請用一行代碼對上述list，按照score排序。

s=[{"name":"Axx","score":"90"},{"name":"Bxx","score":"91"},{"name":"Cxx","score":"20"},]print "original s: ",snew_s = sorted(s,key = lambda e:e.__getitem__('score'))print "new s: ",new_s

結果：

original s:  [{‘score‘: ‘90‘, ‘name‘: ‘Axx‘}, {‘score‘: ‘91‘, ‘name‘: ‘Bxx‘}, {‘score‘: ‘20‘, ‘name‘: ‘Cxx‘}]
new s:  [{‘score‘: ‘20‘, ‘name‘: ‘Cxx‘}, {‘score‘: ‘90‘, ‘name‘: ‘Axx‘}, {‘score‘: ‘91‘, ‘name‘: ‘Bxx‘}]

吐槽：print字典的排序和我s的定義順序貌似不一樣，我定義是name,score，print出來是score再name。貌似也無關緊要，dic本來就無序。

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python 按照list中的dic的某key排序