python 查詢一段字元中所有字母出現的次數,並倒序列出

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 1 # coding:utf-8 2  3 s = """ 4 Have you thought about what you want people to say about you after you’re gone? Can you hear the voice saying, “He was a great man.” Or “She really will be missed.” What else do they say? 5 One of the strangest phenomena of life is to engage in a work that will last long after death. Isn’t that a lot like investing all your money so that future generations can bare interest on it? Perhaps, yet if you look deep in your own heart, you’ll find something drives you to make this kind of contribution---something drives every human being to find a purpose that lives on after death. 6 """ 7  8 dit1 = {} 9 for i in s:10     dit1[i] = s.count(i)11 #print dit112 13 c1 = 014 dit2 = {}15 for ii in dit1.keys():16     if ii.isalpha() is True:17         c1 = c1 +118         dit2[ii] = dit1[ii]19 20 print "all these have %d letter" % c121 print sorted(dit2.items(),key=lambda d:d[1],reverse=True)

 最後一句話是經常用於對dict類型進行排序的方法,其中reverse=True是倒序排列

python 查詢一段字元中所有字母出現的次數,並倒序列出

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