python使用Regex檢測密碼強度源碼分享

來源:互聯網
上載者:User
代碼如下:


#encoding=utf-8
#-------------------------------------------------------------------------------
# Name: 模組1
# Purpose:
#
# Author: Administrator
#
# Created: 10-06-2014
# Copyright: (c) Administrator 2014
# Licence:
#-------------------------------------------------------------------------------
import re
def checklen(pwd):
return len(pwd)>=8
def checkContainUpper(pwd):
pattern = re.compile('[A-Z]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkContainNum(pwd):
pattern = re.compile('[0-9]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkContainLower(pwd):
pattern = re.compile('[a-z]+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkSymbol(pwd):
pattern = re.compile('([^a-z0-9A-Z])+')
match = pattern.findall(pwd)
if match:
return True
else:
return False
def checkPassword(pwd):
#判斷密碼長度是否合法
lenOK=checklen(pwd)
#判斷是否包含大寫字母
upperOK=checkContainUpper(pwd)
#判斷是否包含小寫字母
lowerOK=checkContainLower(pwd)
#判斷是否包含數字
numOK=checkContainNum(pwd)
#判斷是否包含符號
symbolOK=checkSymbol(pwd)
print(lenOK)
print(upperOK)
print(lowerOK)
print(numOK)
print(symbolOK)
return (lenOK and upperOK and lowerOK and numOK and symbolOK)

def main():
if checkPassword('Helloworld#123'):
print('檢測通過')
else:
print('檢測未通過')

if __name__ == '__main__':
main()

平時用正則不多,不知道怎麼寫一個正則滿足要求,用了比較笨的辦法,誰知道一句正則檢驗的請賜教!

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