python的學習筆記/002-5.1（2018-5-21）

標籤：字典(dict)的應用三級菜單

還需要修改

_3_food_list={    ‘主食‘:{        ‘米飯‘:{                 ‘大米飯‘:["大份","中份","小份"],                 ‘小米飯‘:["大份","中份","小份"]                },        ‘麵食‘:{‘面‘:["大份","中份","小份"],                 ‘炒麵‘:["大份","中份","小份"],                 ‘拌面‘:["大份","中份","小份"]                }        },    ‘鍋類‘:{          ‘葷鍋‘:{                   ‘海帶排骨鍋‘:["大鍋","中鍋","小鍋"],                    ‘辣牛肉鍋‘:["大鍋","中鍋","小鍋"]                   },          ‘素鍋‘:{                   ‘豆腐鍋‘:["中鍋","小鍋"],                   ‘珍珠翡翠白玉鍋‘:["大鍋","中鍋","小鍋"]                  }           },    ‘飲品‘:{         ‘奶茶‘:{                  ‘原味奶茶‘:["熱","加冰"],                  ‘草莓奶茶‘:["熱","加冰"]                 },         ‘飲料‘:{                  ‘可口可樂‘:["大杯","中杯"],                  ‘紅牛‘:["大杯","中杯"]               }    }}exit_flag=Falsewhile not exit_flag :    for i in _3_food_list:        print(i)    choice1=input(">>>please input 1:")    while not exit_flag:      if choice1 in _3_food_list:         for i in _3_food_list[choice1]:             print(i)         choice2=input("\t>>>please input 2:")         if choice2 in _3_food_list[choice1]:            for i in _3_food_list[choice1][choice2]:                print(i)            choice3=input("\t\t>>>please input 3 :")            while not exit_flag:                if choice3 in _3_food_list[choice1][choice2]:                     for i in _3_food_list[choice1][choice2][choice3]:                        print(i)                     choice4=input("\t\t\t>>>please iput 4 :")                     if choice4 in _3_food_list[choice1][choice2][choice3]:                           print(choice4 )                           choice5=input(">>>the last back(b):")                           if choice5==‘b‘:                               pass                           elif choice5==‘q‘:                               exit_flag =True                     if choice4==‘b‘:                         break                     elif choice4==‘q‘:                        exit_flag =True                if choice3 == ‘b‘:                   break                elif choice3== ‘q‘:                   exit_flag = True         if choice2 == ‘b‘:             break         elif choice2 == ‘q‘:             exit_flag = True      if choice1 == ‘b‘:          break      elif choice1 == ‘q‘:          exit_flag = True

python的學習筆記/002-5.1（2018-5-21）