題目1501:最大連續子序列乘積

來源:互聯網
上載者:User
#include <stdio.h>#define N  100000+10 double Min[N],Max[N],a[N];double min(double x,double y){  if(x<y) return x;  return y;       } double max(double x,double y){  if(x>y) return x;  return y;       } int main(){    int n;    double ans;   while(scanf("%d",&n)!=EOF)   {       for(int i = 0 ;i <n ; i++)       {          scanf("%lf",&a[i]);               }               Min[0]=a[0];       Max[0]=a[0];       ans = a[0];              for(int i = 1; i < n; i++)       {          Min[i] = min(a[i],min(Min[i-1]*a[i],Max[i-1]*a[i] ));               Max[i] = max(a[i],max(Max[i-1]*a[i],Min[i-1]*a[i] ));              ans = max(ans,Max[i]);        }              int nn=(int)ans;               if(nn==ans)       {         printf("%d\n",nn);         continue;       }       if(ans<0)         printf("-1\n");       else       printf("%.2lf\n",ans);      }    return 0;} 

聯繫我們

該頁面正文內容均來源於網絡整理,並不代表阿里雲官方的觀點,該頁面所提到的產品和服務也與阿里云無關,如果該頁面內容對您造成了困擾,歡迎寫郵件給我們,收到郵件我們將在5個工作日內處理。

如果您發現本社區中有涉嫌抄襲的內容,歡迎發送郵件至: info-contact@alibabacloud.com 進行舉報並提供相關證據,工作人員會在 5 個工作天內聯絡您,一經查實,本站將立刻刪除涉嫌侵權內容。

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.