關於php擷取變數有關問題

關於php擷取變數問題

PHP code

@$judge=$_GET["speed"];if(@$keyboard=$_GET["keyboard"]){$keyboardfinal=100;}if(@$judge==1){if($keyboard<40 && $keyboard>0){@$keyboardfinal=50;    }}if(@$judge==2){if(@$keyboard<50&& $keyboard>0){$keyboardfinal=50;    }}if(@$judge==3 && (@$keyboard<170 && @$keyboard>0)){$keyboardfinal=50;    }

如上代碼~為什麼在第二，三，四個if語句中，即使條件成立任然無法使$keyboardfinal=50;成立為什麼呢？


------解決方案--------------------
@$judge=$_GET["speed"];
[email protected]？
------解決方案--------------------
不明白樓主為什麼要加那麼多錯誤控制符，如果不報出錯誤，你怎麼修改代碼呢？
將樓主的代碼修改了下：

PHP code

$judge = 1;$keyboard = 35;$keyboardfinal = null;switch($judge){    case 1:        if($keyboard<40 && $keyboard>0)            $keyboardfinal=50;        break;    case 2:        if($keyboard<50&& $keyboard>0)            $keyboardfinal=50;        break;    case 3 && ($keyboard<170 && $keyboard>0):        $keyboardfinal=50;        break;}echo "keyboardfinal-->>".$keyboardfinal;#50
------解決方案--------------------
探討
PHP code
@$judge=$_GET["speed"];
if(@$keyboard=$_GET["keyboard"]){
$keyboardfinal=100;
}
if(@$judge==1){
if($keyboard<40 && $keyboard>0){
@$keyboardfinal=50;
    }
}
if(@$judge==2){
if(@$keyb……
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