Regex - PHP 字串中匹配url

需求：

用戶端傳過來一段字串，需要從字串中匹配出所有的url，包括網域名稱或IP後面的參數（含連接埠）

URL範例：

http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23或者http://www.baidu.com/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23

當然簡單URL也是要匹配出來的
求解正則

回複內容：

需求：

用戶端傳過來一段字串，需要從字串中匹配出所有的url，包括網域名稱或IP後面的參數（含連接埠）

URL範例：

http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23或者http://www.baidu.com/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23

當然簡單URL也是要匹配出來的
求解正則

先用比較寬泛的正則匹配出所有的url，例如

https?:\/\/\S+

然後對於這堆url依次採用parse_url函數

^(http|https|ftp)\://[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,3}(:[a-zA-Z0-9]*)?/?([a-zA-Z0-9\-\._\?\,\'/\\\+&%\$#\=~])*$http://regexlib.com/Search.aspx?k=url&c=-1&m=5&ps=20

Java 大概這麼寫

String str = "接收到的字串"String regex = "(http:|https:)//[^[A-Za-z0-9,:\\._\\?%&+\\-=/#]]*";        Pattern pattern = Pattern.compile(regex);        Matcher matcher = pattern.matcher(str);        while (matcher.find()) {            String url=matcher.group();            System.out.println(url);        }

以下字串通過測試.

String str="http://127.0.0.1:6666/ " +                "https://www.baidu.com/ " +                "http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23\n" +                "或者\n" +                "哈哈http://www.baidu.com:85676/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23 6666都是對的";

輸出

http://127.0.0.1:6666/https://www.baidu.com/http://127.0.0.1/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23http://www.baidu.com:85676/metinfo/img/img.php?class1=1&serch_sql=%201=if%28ascii%28substr%28user%28%29,1,1%29%29=114,1,2%29%23

什麼，你問的式PHP？抱歉，我不會PHP。。。
正則一樣的，自己動動腦袋吧。

