根據不同瀏覽器選擇不同css

來源:互聯網
上載者:User

如何根據瀏覽器選擇不同css?比如我有3個CSS檔案,如果用戶端是IE6,則使用CSS1,如果用戶端是IE7或者IE8,則用CSS2,如果用戶端是FIREFOX,則使用CSS3。

從網上找了下,有如下說法

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 

<html xmlns="http://www.w3.org/1999/xhtml"> 

<head> 

<meta http-equiv="Content-Type" content="text/html; charset=gb2312" /> 

<title>根據判斷瀏覽器類型螢幕解析度自動調用不同CSS的代碼</title> 

<link href="" rel="stylesheet" type="text/css" /> 

<script language="jscript"> 

if (window.navigator.userAgent.indexOf("MSIE")>=1) 



var IE1024="style1.css"; 

var IE800="style2.css"; 

var IE1152="css1.css"; 

var IEother="css1.css"; 

ScreenWidth(IE1024,IE800,IE1152,IEother) 

}else{ 

if (window.navigator.userAgent.indexOf("Firefox")>=1) 



//如果瀏覽器為Firefox 

var Firefox1024="style1"; 

var Firefox800="style2.css"; 

var Firefox1152="css1.css"; 

var Firefoxother="css1.css"; 

ScreenWidth(Firefox1024,Firefox800,Firefox1152,Firefoxother) 

}else{ 

//如果瀏覽器為其他 

var Other1024="css1.css"; 

var Other800="css1.css"; 

var Other1152="css1.css"; 

var Otherother="css1.css"; 

ScreenWidth(Other1024,Other800,Other1152,Otherother) 





function ScreenWidth(CSS1,CSS2,CSS3,CSS4){ 

if ((screen.width == 1024) && (screen.height == 768)){ 

setActiveStyleSheet(CSS1); 

}else{ 

if ((screen.width == 800) && (screen.height == 600)){ 

setActiveStyleSheet(CSS2); 

}else{ 

if ((screen.width == 1152) && (screen.height == 864)){ 

setActiveStyleSheet(CSS3); 

}else{ 

setActiveStyleSheet(CSS4); 

}}} 



function setActiveStyleSheet(title){document.getElementsByTagName("link")[0].href=""+title;} 

</script> 

</head> 

<body> 

</body> 

</html>

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