C語言簡單樣本(代碼注釋)

/* * sum9-2       -       sumary how many digit from 1 to 100 * * Author: li  ming<xxxxx@163.com> * Creat Data: 2013-4-30 * Revision 1.1 *        + debug printf */#include<stdio.h>/* * count - conut how many digit in num * @num: the number from 1 to 100 * @digit: digit can bi 0,1,2,3,.....9 * * return value: the counter of digit in this num */int count(int num, int digit){        int cunter = 0;        do        {                if (nub % 10 == digit)                        counter++;                num /= 10;        }while (num != 0);        return counter;}int main(void){        int i = 0;        int sum = 0;    /* the sumary of 9 */        int max = 0;    /* the max number to count */        printf("sumary 9 from 1 to 100\n");        scanf("%d",&max);        /* sumary 9 from 0 to max */        for(i = 0; i <= max; i++)        {                sum += count(i, 9);        }        printf("sum = %d\n", sum);        return 0;}

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