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--1. 舊的解決方案(sql server 2000) create table tb(id int,value varchar(30))insert into tb values(1,‘aa,bb‘)insert into tb values(2,‘aaa,bbb,ccc‘)go --方法1.使用暫存資料表完成SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, value = SUBSTRING(A.[value], B.id, CHARINDEX(‘,‘, A.[value] + ‘,‘, B.id) - B.id)FROM tb A, # BWHERE SUBSTRING(‘,‘ + A.[value], B.id, 1) = ‘,‘ DROP TABLE # --方法2.如果資料量小，可不使用暫存資料表select a.id , value = substring(a.value , b.number , charindex(‘,‘ , a.value + ‘,‘ , b.number) - b.number) from tb a join master..spt_values b on b.type=‘p‘ and b.number between 1 and len(a.value)where substring(‘,‘ + a.value , b.number , 1) = ‘,‘ --2. 新的解決方案(sql server 2005)create table tb(id int,value varchar(30))insert into tb values(1,‘aa,bb‘)insert into tb values(2,‘aaa,bbb,ccc‘)go --方法1.使用xml完成SELECT A.id, B.value FROM( SELECT id, [value] = CONVERT(xml,‘‘ + REPLACE([value], ‘,‘, ‘‘) + ‘‘) FROM tb) A OUTER APPLY( SELECT value = N.v.value(‘.‘, ‘varchar(100)‘) FROM A.[value].nodes(‘/root/v‘) N(v)) B --方法2.使用CTE完成;with tt as (select id,[value]=cast(left([value],charindex(‘,‘,[value]+‘,‘)-1) as nvarchar(100)),Split=cast(stuff([value]+‘,‘,1,charindex(‘,‘,[value]+‘,‘),‘‘) as nvarchar(100)) from tbunion allselect id,[value]=cast(left(Split,charindex(‘,‘,Split)-1) as nvarchar(100)),Split= cast(stuff(Split,1,charindex(‘,‘,Split),‘‘) as nvarchar(100)) from tt where split>‘‘)select id,[value] from tt order by id option (MAXRECURSION 0) DROP TABLE tb
SQLServer 簡單資料拆分
