SQL Server萬用字元妙用

在某些情況下熟悉SQL Server 萬用字元的使用可以協助我們簡單的解決很多問題。

 

--使用_運算子尋找Person表中以an結尾的三字母名字

USEAdventureWorks2012;

GO

SELECT FirstName, LastName

FROM Person.Person

WHERE FirstName LIKE'_an'

ORDER BY FirstName;

 

---使用[^]運算子在Contact表中尋找所有名字以Al開頭且第三個字母不是字母a的人

USEAdventureWorks2012;

GO

SELECT FirstName, LastName

FROM Person.Person

WHERE FirstName LIKE'Al[^a]%'

ORDER BY FirstName;

 

---使用[]運算子尋找其地址中有四位郵遞區號的所有Adventure Works僱員的ID和姓名

USEAdventureWorks2012;

GO

SELECT e.BusinessEntityID, p.FirstName, p.LastName,
a.PostalCode

FROMHumanResources.EmployeeAS e

INNER JOIN Person.PersonAS pON e.BusinessEntityID=
p.BusinessEntityID

INNER JOIN Person.BusinessEntityAddressAS eaON e.BusinessEntityID=ea.BusinessEntityID

INNER JOIN Person.AddressAS aON a.AddressID=
ea.AddressID

WHERE a.PostalCodeLIKE'[0-9][0-9][0-9][0-9]';

 

結果集：

 EmployeeID      FirstName      LastName      PostalCode
----------      ---------      ---------     ----------
290             Lynn           Tsoflias     
3000

 

--將一張表中名字為中英文的區分出來（借鑒論壇中的代碼）

create table tb(namenvarchar(20))

 

insert into tbvalues('kevin')

insert into tbvalues('kevin劉')

insert into tbvalues('劉')

 

select *,'Eng'from tbwherepatindex('%[a-z]%',name)>0and(patindex('%[吖-坐]%',name)=0)

union all

select *,'CN'from tbwherepatindex('%[吖-坐]%',name)>0andpatindex('%[a-z]%',name)=0

union all 

select *,'Eng&CN'from tbwhere(patindex('%[吖-坐]%',name)>0)andpatindex('%[a-z]%',name)>0

 

結果集：

name                

-------------------- ------

kevin                Eng

劉                   CN

kevin劉             Eng&CN

 

(3 row(s) affected)