sqlite學習筆記9：C語言中使用sqlite之插入資料，sqlite學習筆記

sqlite學習筆記9：C語言中使用sqlite之插入資料，sqlite學習筆記

前面建立了一張表，現在給他插入一些資料，插入資料跟建立表差不多，僅僅是SQL語言不一樣而已，完整代碼如下：

#include <stdio.h>#include <stdlib.h>#include "sqlite/sqlite3.h"#define DB_NANE "sqlite/test.db"sqlite3 *db = NULL;char* sql = NULL;char *zErrMsg = NULL;int ret = 0;typedef enum{    false,    true} bool;/*typedef int (*sqlite3_callback)(void*,    Data provided in the 4th argument of sqlite3_exec()int,      The number of columns in rowchar**,   An array of strings representing fields in the rowchar**    An array of strings representing column names);*/static int callback(void *NotUsed, int argc, char **argv, char **azColName){    int i = 0;    for(i=0; i < argc; i++){        printf("%s = %s\n", azColName[i], argv[i] ? argv[i] : "NULL");    }    printf("\n");        return 0;}bool connectDB(){    ret = sqlite3_open(DB_NANE, &db);        if( ret != SQLITE_OK){        fprintf(stderr, "Error open database: %s\n", sqlite3_errmsg(db));        sqlite3_free(zErrMsg);                return false;    }        fprintf(stdout, "Successfully opened database\n");    return true;}bool createTable(){    /* Create SQL statement */    sql = "CREATE TABLE COMPANY("  \    "ID INT PRIMARY KEY     NOT NULL," \    "NAME           TEXT    NOT NULL," \    "AGE            INT     NOT NULL," \    "ADDRESS        CHAR(50)," \    "SALARY         REAL );";        /* Execute SQL statement */    ret = sqlite3_exec(db, sql, callback, 0, &zErrMsg);    if( ret != SQLITE_OK ){        fprintf(stderr, "Error SQL: %s\n", zErrMsg);        sqlite3_free(zErrMsg);                return false;    }        fprintf(stdout, "Successfully table created\n");        return true;}

/*添加了此函數*/bool insertRecords(){    /* Create SQL statement */    sql = "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) "  \    "VALUES (1, 'Paul', 32, 'California', 20000.00 ); " \    "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY) "  \    "VALUES (2, 'Allen', 25, 'Texas', 15000.00 ); "     \    "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)" \    "VALUES (3, 'Teddy', 23, 'Norway', 20000.00 );" \    "INSERT INTO COMPANY (ID,NAME,AGE,ADDRESS,SALARY)" \    "VALUES (4, 'Mark', 25, 'Rich-Mond ', 65000.00 );";        /* Execute SQL statement */    ret = sqlite3_exec(db, sql, callback, 0, &zErrMsg);    if( ret != SQLITE_OK ){        fprintf(stderr, "SQL error: %s\n", zErrMsg);        sqlite3_free(zErrMsg);        return false;    }        fprintf(stdout, "successfully records created\n");    return true;}

bool closeDB(){    int ret = 0;    ret = sqlite3_close(db);    if ( ret == SQLITE_BUSY ){        return false;    }        return true;}int main(int argc, char* argv[]){    connectDB();    /*createTable();*/    insertRecords();    closeDB();        return 0;}

C語言怎向SQLite資料庫插入變數？？

需要使用bind函數 請查看 "查詢參數化"
 
linux下C語言操作sqlite資料庫的問題

拜託 char *sql = " CREATE TABLE SensorData(ID INTEGER PRIMARY KEY,SensorID INTEGER,SiteNum INTEGER,Time VARCHAR(12),SensorParameter REAL);" ;
這裡是你的sql聲明處
隱式的轉換位const char *sql
你後面又對sql進行賦值 也就是對.rodata段進行寫操作 不段錯誤才怪

想要用原麼分配一個大點的buff char sql[512];
要麼動態分配（沒必要）