球隊對手排序問題(java物件導向代碼解)

package wzs.arithmetics;import java.util.ArrayList;import java.util.List;//題目：兩個乒乓球隊進行比賽，各出三人。甲隊為a,b,c三人，乙隊為x,y,z三人。//已抽籤決定比賽名單。有人向隊員打聽比賽的名單。a說他不和x比，c說他不和x,z比，請編程式找出三隊賽手的名單。  public class Test_wzs17{    public static void main(String[] args)    {        // 甲隊成員排序,固定        Pingpang team1Member = new Pingpang("a", "b", "c");        System.out.println("甲隊:" + team1Member);        // 乙隊成員        String[] team2Member =        {                "x", "y", "z"        };        // 乙隊所有的排序可能        List<Pingpang> team2List = new ArrayList<Pingpang>();        // 乙隊臨時排序        Pingpang tempTemp;        for (int i = 0; i < 3; i++)        {            for (int j = 0; j < 3; j++)            {                for (int k = 0; k < 3; k++)                {                    tempTemp = new Pingpang(team2Member[i], team2Member[j], team2Member[k]);                    // 球隊隊員不重複                    if (!tempTemp.member1.equals(tempTemp.member2) && !tempTemp.member2.equals(tempTemp.member3))                    {                        // a說他不和x比，c說他不和x,z比                        if (!tempTemp.member1.equals("x") && !tempTemp.member3.equals("x") && !tempTemp.member3.equals("z"))                        {                            // System.out.println("乙隊:" + tempTemp);                            team2List.add(tempTemp);                        }                    }                }            }        }        for (Pingpang pingpang : team2List)        {            System.out.println("乙球:" + pingpang);        }    }}/** * 乒乓球隊 * @author wWX154783 *  */class Pingpang{    String member1;// 成員1    String member2;// 成員2    String member3;// 成員3    public Pingpang()    {    }    public Pingpang(String member1, String member2, String member3)    {        this.member1 = member1;        this.member2 = member2;        this.member3 = member3;    }    @Override    public String toString()    {        return "球隊成員{" + member1 + "," + member2 + "," + member3 + "}";    }}