linux中Shell指令碼所在目錄的絕對路徑

來源:互聯網
上載者:User
 代碼如下 複製代碼

baseDirForScriptSelf=$(cd "$(dirname "$0")"; pwd)
echo "full path to currently executed script is : ${baseDirForScriptSelf}"

或者


FULLPATH=$(cd "$(dirname "$0")"; pwd)
echo "full path to currently executed script is : ${FULLPATH}"
BASEDIR=`dirname $FULLPATH`
echo "parent dir is $BASEDIR"

這個功能很給力 直接得到絕對路徑 把指令碼整個目錄及上級目錄全部挪窩的好東西

方法二

 代碼如下 複製代碼

#!/bin/sh

name=$0
echo "name : $name"

dir=$(dirname ${name})
echo "dir  : $dir"

path=$(pwd)
echo "path : $path"

path=${dir/./${path}}
echo "path : $path"

執行個體

Shell代碼 

 代碼如下 複製代碼
#!/bin/sh 
this_dir=`pwd` 
dirname $0|grep "^/" >/dev/null 
if [ $? -eq 0 ];then 
                this_dir=`dirname $0` 
else 
        dirname $0|grep "^." >/dev/null 
        retval=$? 
        if [ $retval -eq 0 ];then 
                        this_dir=`dirname $0|sed "s#^.#$this_dir#"` 
        else 
                   this_dir=`dirname $0|sed "s#^#$this_dir/#"` 
        fi 
fi 
echo $this_dir 

當路徑中含有小數點時,該方法會有問題。修正方法為加入一個判斷

 代碼如下 複製代碼

#!/bin/sh
path=$(dirname $0)
if [ ${path:0:1} == . ]
then
path=${path/./$(pwd)}
fi

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