php實現用已經過去多長時間的方式顯示時間

來源:互聯網
上載者:User

   本文執行個體講述了php用已經過去多長時間的方式顯示時間的方法。分享給大家供大家參考。具體如下:

  這裡以一種可讀性比較好的方式顯示已經過去多長時間,比如:距離現在10秒,距離現在1天等等。

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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 function time_is_older_than($t, $check_time){ $t = strtolower($t); $time_type = substr(preg_replace('/[^a-z]/', '', $t), 0, 1); $val = intval(preg_replace('/[^0-9]/', '', $t)); $ts = 0; // (s)econds, (m)inutes, (d)ays, (y)ears if ($time_type == 's'){ $ts = $val; } else if ($time_type == 'm'){ $ts = $val * 60; } else if ($time_type == 'h'){ $ts = $val * 60 * 60; } else if ($time_type == 'd'){ $ts = $val * 60 * 60 * 24; } else if ($time_type == 'y'){ $ts = $val * 60 * 60 * 24 * 365; } else { die('Unknown time format given!'); } if ($check_time < (time()-$ts)){ return true; } return false; }   //使用範例: // timestamp to test: // (could be from an database or something else) $time = 1146722922; // long if check: if (time_is_older_than('30m', $time)){ print 'The given timestamp: ' . date('l dS of F Y h:i:s A',$time); print " - is older than 30 minutes<br/>n"; } else { print 'The given timestamp: ' . date('l dS of F Y h:i:s A',$time); print " - is NOT older than 30 minutes<br/>n"; } // short checks: if (time_is_older_than('10s', $time)){ print "Is older than 10 seconds<br/>n"; } if (time_is_older_than('200m', $time)){ print "Is older than 200 minutes<br/>n"; } if (time_is_older_than('2h', $time)){ print "Is older than 2 hours<br/>n"; } if (time_is_older_than('4d', $time)){ print "Is older than 4 days<br/>n"; } if (time_is_older_than('1y', $time)){ print "Is older than one year<br/>n"; }

  希望本文所述對大家的php程式設計有所協助。

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