Aspx最簡單的 Ajax範例,回傳伺服器的時間

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上載者:User
AjaxPage.aspx
 1 @ Page Language="C#" AutoEventWireup="true" CodeFile="AjaxPage.aspx.cs" Inherits="AjaxPage" %> 2  3 DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> 4  5 <html xmlns="http://www.w3.org/1999/xhtml" > 6 <head runat="server"> 7     <title>Untitled Pagetitle> 8 head> 9 <body>10     <form id="form1" runat="server">11     <div>12     <input type="button" value="Ajax Click" onclick="return GetTime()" />13     div>14     form>15 body>16 html>17 18 <script language="javascript">19 function GetTime()   20 {   21     var xmlhttp = new XMLHttpRequest();22     if (xmlhttp == null) {23         var xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");24     }25     var sPostData = "method=GetTime";26     xmlhttp.open("POST", "AjaxPage.aspx", false);   27     xmlhttp.setRequestHeader("Content-Type","application/x-www-form-urlencoded")28 29     xmlhttp.send(sPostData); 30     alert("現在時間: " + xmlhttp.responseText);31 }     32 script>
AjaxPage.aspx.cs
 1 using System; 2  3 public partial class AjaxPage : System.Web.UI.Page { 4     protected void Page_Load(object sender, EventArgs e) { 5         if (IsPostBack == false && Request["method"] == "GetTime") { 6             GetTime(); 7         } 8     } 9 10     private void GetTime() {11         Response.Clear();12         Response.ContentType = "text/xml";13         Response.Write(DateTime.Now.ToString());14         Response.End();15     }16 }
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