Java中的線程互斥問題

有如下代碼：

public class TraditionalThreadSynchronized {public static void main(String[] args) {new TraditionalThreadSynchronized().init();}public void init() {final Outputer outputer = new Outputer();new Thread(new Runnable() {@Overridepublic void run() {while (true) {try {Thread.sleep(100);} catch (InterruptedException e) {e.printStackTrace();}outputer.out("bbbbbbbbb");}}}).start();new Thread(new Runnable() {@Overridepublic void run() {while (true) {try {Thread.sleep(100);} catch (InterruptedException e) {e.printStackTrace();}outputer.out("aaa");}}}).start();}class Outputer {public synchronized void out(String name) {int len = name.length();for (int i = 0; i < len; i++) {System.out.print(name.charAt(i));}System.out.println();}public void out1(String name) {int len = name.length();synchronized (Outputer.class) {for (int i = 0; i < len; i++) {System.out.print(name.charAt(i));}System.out.println();}}}}

當然，其中的out與out1方法都是可以互斥的，

然而如下代碼中

public class TraditionalThreadSynchronized {public static void main(String[] args) {new TraditionalThreadSynchronized().init();}public void init() {final Outputer outputer = new Outputer();new Thread(new Runnable() {@Overridepublic void run() {while (true) {try {Thread.sleep(100);} catch (InterruptedException e) {e.printStackTrace();}outputer.out("bbbbbbbbb");}}}).start();new Thread(new Runnable() {@Overridepublic void run() {while (true) {try {Thread.sleep(100);} catch (InterruptedException e) {e.printStackTrace();}outputer.out3("aaa");}}}).start();}static class Outputer {public synchronized void out(String name) {int len = name.length();for (int i = 0; i < len; i++) {System.out.print(name.charAt(i));}System.out.println();}public void out1(String name) {int len = name.length();synchronized (Outputer.class) {for (int i = 0; i < len; i++) {System.out.print(name.charAt(i));}System.out.println();}}public synchronized static void out3(String name) {int len = name.length();for (int i = 0; i < len; i++) {System.out.print(name.charAt(i));}System.out.println();}}}

自然，當啟動並執行時候，out與out3兩個方法是不能互斥的，而當線程1執行out1、線程2執行out3的時候，那麼線程將會可以互斥，

那麼怎麼使out與out3兩個方法也可以互斥呢，並不適用out1的方式？

求高人指點