用sql指令碼建立sqlserver資料庫觸發器範例語句

來源:互聯網
上載者:User

複製代碼 代碼如下:--會員表
if object_id('userinfo','u') is not null
drop table userinfo
go
create table userinfo(userid int primary key,user_tegral int,level int)
insert into userinfo select 1,0,0
go
--會員等級表
if object_id('userlevel','u') is not null
drop table userlevel
go

--插入測試資料
create table userlevel(level int primary key,mlevel_point decimal(10,2))
insert into userlevel select 0,0
insert into userlevel select 1,100
insert into userlevel select 2,200
insert into userlevel select 3,300
go

--觸發器
create trigger TR_userInfor
on userinfo for update
as
begin

update a
set a.level=b.level
from userinfo a,userlevel b
where a.userid in(Select userid from inserted) and a.user_tegral>=b.mlevel_point and
a.user_tegral<(Select min(mlevel_point)
from userlevel where mlevel_point>b.mlevel_point)
end

--測試
update userinfo
set user_tegral=100
where userid=1

select * from userinfo

--另外一個觸發器
set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go
ALTER TRIGGER [AlterName]
ON [dbo].[FS_User]
FOR INSERT
AS
BEGIN
SET NOCOUNT ON;
UPDATE dbo.FS_User SET uname=(SELECT uname FROM Inserted)+'@ml'
WHERE id IN (SELECT id FROM inserted)
END

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