asp下用datediff實現計算兩個時間差的函數

計算兩個時間差的函數

'******************************
'||Function TimeDiff(sBegin, sEnd)
'||本Function Compute兩個時間的差，可以不用更改直接使用
'||作者：machinecat 2001/10/26
'******************************

'******************************
'註：首先需要判斷使用者輸入的sBegin與sEnd之間的大小
'可以通過DataDiff函數獲得兩者之間的時間差，不需要進行複雜的時間換算
'******************************

Function TimeDiff(sBegin, sEnd)
Dim iHourB, iMinuteB, iSecondB, iMiniSecondB
Dim iHourE, iMinuteE, iSecondE, iMiniSecondE
Dim dTimeB, dTimeE, dTimeDiff
Dim iHour, iMinute, iSecond, iMiniSecond

iHourB = clng(Left(sBegin, 2))
iMinuteB = clng(Mid(sBegin, 4, 2))
iSecondB = clng(Mid(sBegin, 7, 2))
iMiniSecondB = clng(Mid(sBegin, 10, 4))

iHourE = clng(Left(sEnd, 2))
iMinuteE = clng(Mid(sEnd, 4, 2))
iSecondE = clng(Mid(sEnd, 7, 2))
iMiniSecondE = clng(Mid(sEnd, 10, 4))

dTimeB = iHourB * 3600 + iMinuteB * 60 + iSecondB + iMiniSecondB / 1000
dTimeE = iHourE * 3600 + iMinuteE * 60 + iSecondE + iMiniSecondE / 1000
dTimeDiff = dTimeE - dTimeB

iHour = Int(dTimeDiff / 3600)
dTimeDiff = dTimeDiff - iHour * 3600
iMinute = Int(dTimeDiff / 60)
dTimeDiff = dTimeDiff - iMinute * 60
iSecond = Int(dTimeDiff)
dTimeDiff = dTimeDiff - Int(dTimeDiff)
iMiniSecond = dTimeDiff

TimeDiff = iHour & "小時" & iMinute & "分鐘" & iSecond & FormatNumber(iMiniSecond, 3) & "秒"
End Function