利用python實現冒泡排序

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1、先生存一個隨機數組成的list

2、然後進行排序，把大的元素放在後面，小的元素放在前面，最終實現從小到大排列

首先生存一個隨機數組成的list

import random# print(sys.path)# print(__file__)l1 = []for i in range(6):    i = random.randrange(0,165535)    l1.append(i)print(l1)[72764, 163851, 54255, 51053, 106289, 48579]

 

然後對這個列表進行排序

r = len(l1)for m in range(r-1):    a = 0    for n in range(r-1):        if l1[a] > l1[a + 1]:             tmp_before = l1[a]             tmp_after = l1[a + 1]             l1[a] = tmp_after             l1[a + 1] = tmp_before             # print(l1)        elif l1[a] == l1[a + 1]:            s = "l1[%s]和l1[%s]相等,這次不用替換" %(a,a+1)            print(s.center(40,"-"))            pass        else:            s = "l1[%s]比l1[%s]小,這次不用替換" % (a, a + 1)            print(s.center(40,"-"))            pass        a += 1print(l1)[48579, 51053, 54255, 72764, 106289, 163851]

 

利用python實現冒泡排序