Using this when not in object context in_PHP教程

問題
Using $this when not in object context in
解決方案
private $link_id;

private $sql;

private $getAll = array();

private $getOne = array();

private $qRes;

public static function _init(&$dsn, $pconnect = FALSE, $halt = TRUE) {

if(!is_array($dsn)) exit('Error, Dsn not is array');

$dsn['host'] = (isset($dsn['host']))?$dsn['host']:'localhost';

$dsn['login'] = (isset($dsn['login']))?$dsn['login']:'root';

$dsn['dbpwd'] = (isset($dsn['dbpwd']))?$dsn['dbpwd']:NULL;

$dsn['db'] = (isset($dsn['db']))?$dsn['db']:'test';

$dsn['char'] = (isset($dsn['char']))?str_replace('-', NULL, $dsn['char']):'utf8';

if($pconnect) {

if(!$this->link_id = @mysql_pconnect($dsn['host'], $dsn['login'], $dsn['dbpwd'])) {

$halt && $this->getErrorMsg(__LINE__);

}

} else {

if(!$this->link_id = @mysql_connect($dsn['host'], $dsn['login'], $dsn['dbpwd'])) {# 執行到這裡出錯。。

$halt && $this->getErrorMsg(__LINE__);

}

}


複製代碼


參考答案
static function 中 用 self
參考答案
靜態函數裡用self!!!!!!!!!!!!!!!
參考答案
....我現在沒用static，現在是public function 他還是報錯
參考答案
那就是沒這方法

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