[WinForm][DevExpress][TreeList]節點互斥

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關鍵代碼：

        /// <summary>        /// 節點互斥同步        /// 說明        /// eg:        ///TreeListNode _node = e.Node;        ///_node.SyncMutexNodeCheckState(_node.CheckState, n => n.GetNodeType() == NodeType.Cab);        /// </summary>        /// <param name="node">需要互斥同步的節點</param>        /// <param name="checkState">節點狀態</param>        /// <param name="checkHanlder">互斥條件【委託】</param>        public static void SyncMutexNodeCheckState(this TreeListNode node, CheckState checkState, Predicate<TreeListNode> checkHanlder)        {            TreeList _tree = node.TreeList;            if (checkHanlder(node))//當前節點符合互斥條件時候            {                _tree.DownRecursiveTree(n => n.CheckState = CheckState.Unchecked);            }            else            {                TreeListNode _curParentNode = node.GetParentNode(checkHanlder);//擷取符合互斥條件的父節點                if (_curParentNode == null) return;                TreeListNode _thePubleNode = node.GetPublicParentNode(checkHanlder);//擷取符合互斥條件的公用父節點                if (_thePubleNode == null) return;                foreach (TreeListNode n in _thePubleNode.Nodes)                {                    foreach (TreeListNode nc in n.Nodes)                    {                        if (nc != _curParentNode)                        {                            nc.CheckState = CheckState.Unchecked;                            nc.DownRecursiveNode(nr => nr.CheckState = CheckState.Unchecked);                        }                    }                }            }            node.SyncNodeCheckState(checkState);            node.CheckState = checkState;        }    }

        /// <summary>        /// 向上遞迴，擷取合格節點的公用父節點        /// </summary>        /// <param name="node">動作節點</param>        /// <param name="checkHanlder">委託</param>        /// <returns>合格節點</returns>        public static TreeListNode GetPublicParentNode(this TreeListNode node, Predicate<TreeListNode> checkHanlder)        {            TreeListNode _publicPNode = null;            TreeListNode _findNode = node.GetParentNode(checkHanlder);//先擷取到條件判斷的自身父節點            if (_findNode != null)            {                //開始向上遞迴                UpwardRecursiveNode(_findNode, n =>                {                    TreeListNode _curpublicNode = n.ParentNode;//擷取當前向上遞迴的父節點                    if (_curpublicNode != null)                    {                        if (_curpublicNode.Nodes.Count > 1)//若有多個子節點，則是公用父節點                        {                            _publicPNode = _curpublicNode;                            return false;//跳出遞迴                        }                    }                    return true;//繼續遞迴                });            }            return _publicPNode;        }

        /// <summary>        /// 向上遞迴，擷取合格父節點        /// </summary>        /// <param name="node">需要向上遞迴的節點</param>        /// <param name="conditionHanlder">判斷條件【委託】</param>        /// <returns>合格節點【TreeListNode】</returns>        public static TreeListNode GetParentNode(this TreeListNode node, Predicate<TreeListNode> conditionHanlder)        {            TreeListNode _parentNode = node.ParentNode;//擷取上一級父節點            TreeListNode _conditonNode = null;            if (_parentNode != null)            {                if (conditionHanlder(_parentNode))//判斷上一級父節點是否符合要求                {                    _conditonNode = _parentNode;                }                if (_conditonNode == null)//若沒有找到符合要求的節點，遞迴繼續                    _conditonNode = GetParentNode(_parentNode, conditionHanlder);            }            return _conditonNode;        }SyncNodeCheckState代碼參考：http://www.cnblogs.com/Yan-Zhiwei/p/3808089.html

說明：

，Test3和蒙自路Test2都是"cab"類型；

當調用代碼如下：

            TreeListNode _node = e.Node;            _node.SyncMutexNodeCheckState(_node.CheckState, n => n.GetNodeType() == NodeType.Cab);

實現的效果就是要麼只能勾選“Test3”或者“蒙自路Test2”節點或者子節點，不同同時勾選，應該就是互斥的意思；也是這段代碼想實現的效果，希望有所協助。