在oracle中編寫樹級代碼

來源:互聯網
上載者:User
oracle
create table Dept(
 DepartNO  varchar2(10),
   DepartName  varchar2(20),
 TopNo    varchar2(10));

insert into Dept values('001','董事會','0');
insert into Dept values('002','總裁辦','001');
insert into Dept values('003','財務部','001');
insert into Dept values('004','市場部','002');
insert into Dept values('005','公關部','002');
insert into Dept values('006','銷售部','002');
insert into Dept values('007','分銷處','006');
insert into Dept values('008','業務拓展處','004');
insert into Dept values('009','銷售科','007');

CREATE TABLE TempDept
(
 TempdeptNo    char(4), /*部門編號*/
 TempdeptName   varchar2(20), /*部門名稱*/
  UpperTempdeptNo  char(4), /*上層業務編號*/
  UpperTempdeptName  varchar2(20), /*上層業務名稱*/
 TempdeptLevel   number(4) /*部門所處的層級*/
);

select departname
from dept
connect by prior departno=topno
start with topno='0';

select a.departname top ,b.departname next
from dept a,dept b
where a.departno=b.topno;

select lpad(departno,level*2+length(departno),'\')
from dept
start with topno='0'
connect by prior departno=topno;

select departno,departname,level ||'\'|| topno
from dept
start with topno='0'
connect by prior departno=topno;

select lpad(departno,level*2+length(departno),' ')
from dept
start with topno='0'
connect by prior departno=topno;

select lpad(departno,level*3,' ')


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