1 49 random number generator

A recent project reminds me of a very simple way to generate a pseudo-random number to create a raindrop's behavior. I found that if we had a randomly initialized unsigned 32-bit seed n could loop through a pseudo-random number (C) using only 14-character multiplication tables: n*=0x9e3779b1; Each time you apply this

identifier token that is saved to the session and is written back to the form as a hidden element, and the token attribute in the session is deleted after the form is processedAfter the user submits the form, the server authenticates:1, whether there is a token element, there is the next step, do not process the form2, if there is a token attribute in the session, proceed to the next step, do not process the form3, the token attribute value in the se

) - { - if(n1) in { -ans_matrix[0][0]=KSC (ans_matrix[0][0],matrix[0][0]); toans_matrix[1][0]= (KSC (ans_matrix[1][0],matrix[0][0]) +matrix[1][0])%m; + } -n>>=1; thell TMP1=KSC (matrix[0][0],matrix[0][0]); *ll tmp2= (KSC (matrix[1][0],matrix[0][0]

, LL AMP;GCD) {if(!B) {x=1,y=0, Gcd=a;return; } EXGCD (B,a%b,y,x, GCD);y=y-a/b*x;} ll Get_inv (LLx, ll MOD) {ll x,y,gcd; EXGCD (x, MOD,X,Y,GCD);return(X%mod+MOD)%mod;} void Bsgs (ll a,ll b,ll C) {init (); llm=(int) Ceil (sqrt(C)); ll k=1; for(intI=0;im; i++) {intflag=1; for(intJ=head[k%mod];j!=-1; J=edge[j].Next)

\[\begin{eqnarray*}x_i=x_{i-1}+x_{i-2}\\x_i^2=x_{i-2}^2+x_{i-1}^2+2x_{i-2}x_{i-1}\\x_{i-1}x_i= (X_{i-3}+x_{i-2}) (x_{i-2}+x_{i-1}) \ \=2x_{i-3}x_{i-2}+x_{i-2}x_{i-1}+x_{i-3}^2+x_{i-2}^2\end{eqnarray*}\]Therefore, the transfer matr

Import Java.util.scanner;public class Random {public static void main (string[] args) {//TODO auto-generated method Stubsy Stem.out.print ("Enter the number of random numbers you want to get:"); Scanner Scanner = new Scanner (system.in); int n = scanner.nextint ();//Gets the number of

Matrix Fast power ... + fast multiply on OK--------------------------------------------------------------------------------------#include using namespace std;typedef long Long ll;ll MOD, A, C, X, N, G;ll MUL (ll A, ll b) {ll ans = 0;for (; b; b >>= 1) {if (b 1) ans + = A;if (ans >= mod) ans-= mod;a if (a >= mod) A-= mod;}return ans;}struct Matrix {ll x[2][2];Matrix () {memset (x, 0, sizeof x);}inline void

public class Random {private static final int a=48271;private static final int m=2147483647;private static final int q=m/a;private static final int r=m%a;public Random () {This ((int) (System.currentt Imemillis ()%integer. Max_value));} /*construct this b random object with specified inital state * */public Random (int

Question :..... Take a long look. First, since the Lexicographic Order of the sorted sequence is the smallest, You must select as few numbers as possible. Then T is 1 ~ The M * n sequence does not exist. (At the beginning, I missed this condition) Okay, this question is greedy.Select the minimum point that is not marked each time, and mark both the lower left and the upper right corner (remember to mark the duplicate break, otherwise it will be dow

It is generally used to set random number generation. srand((unsigned)time( NULL )); Because the above settings are based on time, the random number is unpredictable! In fact, this is a pseudo-random number, and the computer c

1. Seeds and distribution Five types of distributions are introduced here, including the following: (a), and (). Parameters required for distribution and use are provided. 2. Test the random number generator. This section contains only one simple example, which is not described in detail. The following is the procedure

=shared--enable-disk_cache=shared--enable-mem_cache=shared-- enable-proxy=shared--enable-proxy_connect=shared--enable-proxy_ftp=shared--enable-proxy_http=shared-- enable-file_cache=shared--enable-charset_lite=shared--enable-case_filter=shared--enable-case_filter_in=shared- -enable-ssl=shared--WITH-APR=/USR/LOCAL/APR--with-apr-util=/usr/local/apr-utilMakeMake installNot that the first method must have a problem, I have also encountered the first installation is available, if you are the first way

Today with the doctrine in preparation for a party, there is a random number lottery to make the link, want me to make a random number generator, preferably the kind of start after the number of jumps, the key after the pause.This

; - } -T/=D; the ll x, y; the EXGCD (a,b,x,y); thex= (x*t)%p; the while(x0) x+=p; - returnx+1; the } thell C=pow (A-1, P-2); thell a= (b*c+x1)%p,b=p,t= (b*c+t)%p;94 if(a0) a= (a+p)%p; the if(b0) b= (b+p)%p; thell d=gcd (A, b); the if(t%D) {98 return-1; About } -T/=D;101 ll x, y;102 EXGCD (a,b,x,y);1

A whole bunch of borders was not known at first, and after a few random sentences, WAHelpless to download the data, and then crazy to judge all kinds of strange boundariesTo gouge out the boundary problemFirst we consider the situation of a=1X1+k*b=t (mod p)EX_GCD can be solvedConsider the situation of a>1Make s=x+b/(A-1)The original is becoming a geometric series.S1*a^k= (t+b/(A-

Prioritize the processing of arrays in the way it describesAnd then, in order to get as many small numbers as possible in the sequence,So 1 is a must to appear, in order to make the whole sequence of the order of the dictionary after the smallest.We thought, if 2 could be in this series, it'd be better.But 2 may not be in this series, that is, 2 walk 1 is impossible to go to the place, you can not walk 2.So

Huawei WS318 predictable random number generator Vulnerability Release date:Updated on: Affected Systems:Huawei WS318Huawei WS318Description:Bugtraq id: 71787 Huawei WS318 is a wireless router product. A predictable random number gen