1090. In the Army nowtime limit:1.0 secondMemory limit:64 MBThe sergeant ordered that all the recruits stand in rows. The recruits has formedKRows withNPeople in each, but failed to stand according to their height. The right-stand in a row is as Following:the first soldier must be the highest, the second must being the second high EST and so on; The last soldier in a row must is the shortest. In order to teach the "people" to form rows, the sergeant o
Geek DIY: cheap TV rod play GNSS-SDR, real-time GPS Positioning
0 × 00 Preface
FreeBufPopular Science:
GPS is short for Global Navigation Satellite System. Chinese name: global satellite navigation system and global navigation satellite system.
GPS refers to all satellite navigation systems, including global, regional, and enhanced systems, such as GPS in the United States, Glonass in Russia, Galileo in Europe, and Beidou satellite navigation system
This article was written by Taylor Killian on his blog in August 13. He contrasted the three parity SDR platforms, thinking that the three products would be the most popular SDR platform of the coming year. I think this article is very valuable for reference, a simple translation of a turn around.The original is here:Http://www.taylorkillian.com/2013/08/sdr-showd
0x00 PrefaceGNSS is an abbreviation for the Global Navigation satellite system. Chinese is called: Global satellite navigation system, global navigation satellite system.GNSS refers to all satellite navigation systems, including global, regional and enhanced, such as the U.S. GPS, Russian GLONASS, European Galileo, China's Beidou satellite navigation system, and related enhancement systems, such as the United States of WAAS (wide area enhancement system), Europe's EGNOS (European static navigati
0x00 written at the beginningRecently, the discovery of crazy Danish hacker on YouTube released a very good tutorial video: Use SDR sniffing visits to listen to GSM network traffic (GSM sniffing Teaser–software Defined Radio Series). This tutorial is illustrated in detail from the installation of a TV stick to scanning, the use of sniffer tools, and the capture and decryption of GSM traffic packets:As a porter, here will be divided into two or three p
Tags: sampling parameters Enter ENC Compare Direct circuit board enable AnnHardware PreparationAntenna: A dangling long-distance antenna, if only temporary use, directly with the ordinary 0.75 square PVC multi-stranded soft wire can be.Baron: 9:1 BarronReceiver: Q Channel adds RTL-SDR receiver for low frequency inputand the corresponding connection cable.ReceiverThe front and back of the circuit board, the connecting head is SMA, the outer screw inner
1. SDR descriptionSpring Data Redis (SDR), a set of simplified access to Redis APIs provided by Springframework, is another layer of encapsulation for Jedis.The SDR integrates the four open-source Redis Connector of Jedis,jredis,srp,lettuce, all of which are open source Java libraries for Redis. Among them, Jredis and SRP start from spring-data-redis1.7, it is no
Objective: To set up an SDR server, through the terminal can connect to the Server to operate on its SDR, to achieve remote operation of the station, so as not to be affected by the antenna, the antenna hanging in the sun the most non-partner place, find a cool to hold the computer listening to the radio.
Client scenario 1:RTL-SDR + gqrx/
easy to click on the wrong spot: Errors caused by the spring version too low"Environment Parameters"Redis version: Redis-2.4.5-win32-win64Spring Original version: 4.1.7.RELEASESpring Modified version: 4.2.6.RELEASE"Description of the barrier"Question:nosuchmethoderrorInvocation of Init method failed; Nested exception is java.lang.NoSuchMethodError:Org.springframework.core.serializer.support.deserializingconverter."Cause analysis"Cause: Spring version is too lowIn the
1090 plus two fork tree2003 NOIP National League Improvement Grouptime limit: 1 sspace limit: 128000 KBtitle level: Diamonds Diamond SolvingTitle DescriptionDescriptionThe mid-order traversal of a two-ary tree with an n node is (l,2,3,..., N), where the number,..., n is a node number. Each node has a fraction (all positive integers), the score for the J node is di,tree and each of its subtrees has an extra point, and any subtrees tree subtree (also in
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1090: [SCOI2003] string folding time
limit: ten Sec
Memory Limit: 162 MB
Submit: 826
Solved: 533
[Submit] [Status] [Discuss]
DescriptionThe definition of folding is as follows: 1. A string can be seen as its own folding. Remember it as s? S 2. X (S) is the folding of the string of X (x>1) s connected together. Remember as X (S)? SSSS ... s (x s). 3. Wha
1090. Highest price in supply Chain (25)A supply chain is a network of retailers (retailer), distributors (dealer), and suppliers (supplier)--everyone involved in moving a produ CT from supplier to customer.Starting from one root supplier, everyone on the chain buys products from one's supplier in a price P and sell or Distribu Te them in a price, is r% higher than P. It is assumed this member in the supply chain have exactly one supplier except the r
1090: [SCOI2003] String foldingTime Limit:1 SecMemory limit:256 MBTopic Connection http://www.lydsy.com/JudgeOnline/problem.php?id=1090DescriptionThe definition of folding is as follows: 1. A string can be seen as its own folding. Remember it as s? S 2. X (S) is the folding of the string of X (x>1) s connected together. Remember as X (S)? SSSS ... s (x s). 3. What if a? A ', B? B ', then AB? A ' B ' For example, because 3 (a) = AAA, 2 (B) = BB, so 3 (
The key to this question is how you choose to calculate the bricks that need to be added, starting from the height of the child or from the big height. The main subject is a new array to store the number of bricks starting from the largest (maximum height) brick. In the Code "for (int k=m;k>=1;k--)"Then through the following str[iii][j]= ' 1 '; To make up, and then calculate the number of bricks of the second largest height. And so on, come to a conclusion.#include #includeusing namespacestd;Con
Link: Sicily 1090 Ideas:
Simple Minimum Spanning Tree problem. Use the prim algorithm here. Use the visited array to record whether each node has been accessed, that is, whether it is already in the minimal spanning tree. Each time, a node with the smallest key value is extracted from the node in the minimal spanning tree and put it into the spanning tree. The key value indicates the minimum distance between the node and the point set in t
Here is the link to the question:
Http://acm.zju.edu.cn/onlinejudge/showProblem.do? ProblemCode = 1090 the topic description is very simple. The coordinates of the three points are given, which are set to A (x1, y1), B (x2, y2), C (x3, y3 ), then obtain the circumference of the circle through these three points (retain two decimal places ). However, it is troublesome to deduce the formula. I did this. First, it is difficult to obtain the diameter of t
Title DescriptionV8 super like to exercise, especially like to climb trees, in order to catch more insects, he hopes that his own from a leaf node to the root node of the longest path, now give you a tree, output V8 required path length.InputMultiple sets of dataThe first line, a T, represents the number of data groupsFor each set of data that followsThe first row is an N, which represents the number of sides.The next n rows, each line three number u,v,w, indicate that there is a son with V is U
two number and stored in the array B, to sort a (the original array) and B array, to determine a[i=0]+b[j= (n (n-1))]=0?, if three number 22 and equal to 0, then to the result array, (guaranteed output results are not duplicated), The final output result set. See the code, write a bit messy, hope forgive me!AC Code:Four-digit and whether 0http://www.51nod.com/onlineJudge/questionCode.html#!problemId=1267given n integers, you can determine if you can choose 4 numbers, and they are 0, then output
Topic: Given a string, in accordance with the problem of the compression method to the shortest possible compression to how longInterval DP Order F[i][j] Indicates how long a string within the [I,j] interval can be compressed toNormal interval dp:f[i][j]=min{f[i][k]+f[k+1][j]} (iIn addition, if the string is compressed, then we can enumerate the loop section, using hash to determineIf k is a cyclic section, then there is f[i][j]=min (f[i][j],f[i][i+k-1]+digit[len/k]+2)Where len=j-i+1,digit repre
Test Instructions:LinkMethod:Interval DP parsing: ZXR I'll take this one after a few days to finish the problem. Just remember what interval DP? OK, and then I do this problem with the heart of the SB-problem. This question is SB problem, this problem is SB problem, this problem is SB problem, grace important words three times. F[I][J] means I to j folds the smallest length. Transfer is a tease. Enumeration of the middle point K, one is i~k can not become the k+1~j of the circular section, then
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